[英]pointer to function c++
guys! 伙计们! I am trying to do this:
我想这样做:
int (*filterFunc)(Medicine* criteria, Medicine*);
DynamicVector<Medicine>* filter2(Medicine* criteria, filterFunc f); //error
but I get an error: 'filterFunc' is not a type 但我收到一个错误:'filterFunc'不是一个类型
I am trying to do this because I want a general filter so then I can do this: 我试图这样做,因为我想要一个通用过滤器,所以我可以这样做:
int filterPrice(Pet* pet) {
if (pet->price > 10 && pet->price < 100) {
return 0;
}
return 1;
}
VectorDinamic* filter2(Pet* criteria, filterFunc f) {
VectorDinamic* v = getAll(ctr->repo);
VectorDinamic* rez = creazaVectorDinamic();
int nrElems = getNrElemente(v);
int i;
for (i = 0; i < nrElems; i++) {
Pet* pet = get(v, i);
if (!f(criteria, pet)) {
add(rez, copyPet(pet));
}
}
return rez;
}
VectorDinamic* filterByPrice(float price) {
Pet* criteria = createPet(1, "", "", price);
VectorDinamic* rez = filter2(ctr, criteria, filterByPriceGr);
destroyPet(criteria);
return rez;
}
How can I solve this problem? 我怎么解决这个问题?
You forgot a typedef
, to declare the type. 你忘了一个
typedef
来声明这个类型。 Otherwise this declaration just creates a variable of type int(*)(Medicine*,Medicine*)
. 否则,此声明只会创建一个
int(*)(Medicine*,Medicine*)
类型的变量int(*)(Medicine*,Medicine*)
。
typedef int (*filterFunc)(Medicine* criteria, Medicine*);
//^^^^^^^
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