如何调用存储在作为另一个函数的参数的对象中的函数？

Question

I'll be honest, I'm in way over my head with this one. Any help would be appreciated.

OBJECTIVE

I want to call a function called restart, but the function is inside an object and is being passed to a function Class.extend .

The code I'm working with is

    var Chickenz = Class.extend(
{
        init: function(value) 
        {
           //do something
        },
        // restart game
        restart: function() 
        {
            this.score.restart();  
            //etc
        }
});

What have I tried?

restart(); Doesn't work. I get TypeError: restart is not a function No biggy I didn't expect it to work. Based on this question > Javascript - Storing function in object - bad practice? I thought I could do something like Chickenz.restart(); but it's more complicated, because of Class.extend

I've included code for Class.extend towards the bottom of this question.

Later the restart function is called with the following code

/* GUI Events */
            // restart button
            addEvent($("restart"), "click", function() {
                self.restart();
                return false;
            });

I thought I would try self.restart(); but that didn't work- TypeError: self.restart is not a function.

So my question.

How can I call the restart function?

CODE for Class.extend

var initializing = false;
  // The base Class implementation (does nothing)
  this.Class = function(){};
  // Create a new Class that inherits from this class
// Create a new Class that inherits from this class
  Class.extend = function(prop) {
    var _super = this.prototype,
        prototype,
        name,
        tmp,
        ret;

    // Instantiate a base class (but only create the instance,
    // don't run the init constructor)
    initializing = true;
    prototype = new this();
    initializing = false;

    // Copy the properties over onto the new prototype
    for ( name in prop ) {
      // Check if we're overwriting an existing function
      prototype[name] = typeof prop[name] == "function" &&
        typeof _super[name] == "function" ?
        (function(name, fn){
         return function() {
           tmp = this._super;
           // Add a new ._super() method that is the same method
           // but on the super-class
           this._super = _super[name];
           // The method only need to be bound temporarily, so we
           // remove it when we're done executing
           ret = fn.apply(this, arguments);
           this._super = tmp;
           return ret;
         };
        })(name, prop[name]) :
        prop[name];
    }
    // The dummy class constructor
    //Changed according to http://ejohn.org/blog/simple-class-instantiation/    
    //Use the new operator to instantiation                                     
        function Class(args){
                if ( this instanceof arguments.callee ) {
                    if ( !initializing && this.init )
                        this.init.apply( this, args.callee ? args : arguments );
                } else
                    return new arguments.callee( arguments );
            };

    // Populate our constructed prototype object
    Class.prototype = prototype;
    // Enforce the constructor to be what we expect
    Class.constructor = Class;
    // And make this class extendable
    Class.extend = arguments.callee;
    return Class;
 };

Answer 1

You appear to be basing this on John Resig's example here You should look at how he does it :)

Class.extend returns a constructor for a class. You can just create an instance of the class and then call it.

You need something like:

var chicken = new Chickenz();

chicken.restart();

Note that this will immediately throw an error right now though, because this will then be bound to the new chicken object, and the chicken doesn't have a score.restart function unless you have other code you aren't showing us. I have no idea what you want that line to do, but you'll need to add a score property with a restart method to the chicken object or have the restart method reference something else.