[英]sublist to dictionary
So I have:所以我有:
a = [["Hello", "Bye"], ["Morning", "Night"], ["Cat", "Dog"]]
And I want to convert it to a dictionary.我想把它转换成字典。
I tried using:我尝试使用:
i = iter(a)
b = dict(zip(a[0::2], a[1::2]))
But it gave me an error: TypeError: unhashable type: 'list'
但它给了我一个错误: TypeError: unhashable type: 'list'
Simply: 只是:
>>> a = [["Hello", "Bye"], ["Morning", "Night"], ["Cat", "Dog"]]
>>> dict(a)
{'Cat': 'Dog', 'Hello': 'Bye', 'Morning': 'Night'}
I love python's simplicity 我喜欢python的简单性
You can see here for all the ways to construct a dictionary: 您可以在此处查看构建字典的所有方法:
To illustrate, the following examples all return a dictionary equal to
{"one": 1, "two": 2, "three": 3}
: 为了说明,以下示例都返回等于{"one": 1, "two": 2, "three": 3}
的字典{"one": 1, "two": 2, "three": 3}
:
>>> a = dict(one=1, two=2, three=3)
>>> b = {'one': 1, 'two': 2, 'three': 3}
>>> c = dict(zip(['one', 'two', 'three'], [1, 2, 3]))
>>> d = dict([('two', 2), ('one', 1), ('three', 3)]) #<-Your case(Key/value pairs)
>>> e = dict({'three': 3, 'one': 1, 'two': 2})
>>> a == b == c == d == e
True
Maybe you can try this following code:也许你可以试试下面的代码:
a = [
["Hello", "Bye"],
["Morning", "Night"],
["Cat", "Dog"]
]
b = {}
for x in a:
b[x[0]] = x[1]
print(b)
And if you want your value have more than 1 value (in the form of a list), you can slightly change the code:如果你希望你的值有超过 1 个值(以列表的形式),你可以稍微更改代码:
b[x[0]] = x[1]
to code:编码:
b[x[0]] = x[1:]
Hope it will help you:)希望它能帮助你:)
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