使用Ajax成功处理程序返回JSON对象

Question

I am using an Ajax command to query data from a local server and I need to return a JSON object via the success handler.

My Ajax command looks like this:

var json = $.ajax({
    url: 'http://localhost:9200/wcs/routes/_search',
    type: 'POST',
    data: JSON.stringify({
        "query": {
            "match_all": {}
        }
    }),
    dataType: 'json',
    async: false
});

I'd like to return the JSON document in the variable that I already have assigned: json

Could I do something like this in the command? (I know this isn't correct code):

success: return(json);
});

Answer 1

You were close,

var json;
$.ajax({
    url: 'http://localhost:9200/wcs/routes/_search',
    type: 'POST',
    data :
        JSON.stringify(
            {
                "query" : { "match_all" : {} }
        }),
    dataType : 'json',
    async: false,
    success: function(data){
        json = data;
    }
})
console.log(json);

but async: false is a bad idea, so i'd suggest using json inside the callback.

$.ajax({
    url: 'http://localhost:9200/wcs/routes/_search',
    type: 'POST',
    data :
        JSON.stringify(
            {
                "query" : { "match_all" : {} }
        }),
    dataType : 'json',
    //async: false,
    success: function(data){
        console.log(data);
    }
})

Answer 2

Success expect's A function to be called if the request succeeds.

You can do this :

var json:
....
....

success: function(data){
       json = data;
   }
});

Answer 3

 var arr = new Array();
 success: function (data) {
    $.map(data, function (item) {
          arr.push({
              prop_1: item.prop_1,
              prop_2: item.prop_2,
              prop_3: item.prop_3
             });
           });
      }

You can rename prop_1, prop_2 vs up to your codebehind