如何使用正则表达式和str.replace格式化

Question

I am using this regular expression

var str = "The requirements of this chapter apply to the following: (1)New buildings or portions thereof used as health care occupancies (see 1.4.1) (2)Additions made to, or used as, a health care occupancy (see 4.6.6 and 18.1.1.4) Exception: The requirement of 18.1.1.1.1 shall not apply to additions classified as occupancies other than health care that are separated from the health care occupancy in accordance with 18.1.2.1(2) and conform to the requirements for the specific occupancy in accordance with Chapters 12 through 17 and Chapters 20 through 42, as appropriate. (3)Alterations, modernizations, or renovations of existing health care occupancies (see 4.6.7 and 18.1.1.4) (4)Existing buildings or portions thereof upon change of occupancy to a health care occupancy (see 4.6.11) Exception*: Facilities where the authority having jurisdiction has determined equivalent safety has been provided in accordance with Section 1.5.";
str = str.replace(/(\(\d+\)|exception\s*\:*)/gi, "<br /><br />$1&nbsp");

where I get output like this

18.1.1.1.1 The requirements of this chapter apply to the following:

(1) New buildings or portions thereof used as health care occupancies (see 1.4.1)

(2) Additions made to, or used as, a health care occupancy (see 4.6.6 and 18.1.1.4)

Exception: The requirement of 18.1.1.1.1 shall not apply to additions classified as occupancies other than health care that are separated from the health care occupancy in accordance with 18.1.2.1

(2) and conform to the requirements for the specific occupancy in accordance with Chapters 12 through 17 and Chapters 20 through 42, as appropriate.

(3) Alterations, modernizations, or renovations of existing health care occupancies (see 4.6.7 and 18.1.1.4)

(4) Existing buildings or portions thereof upon change of occupancy to a health care occupancy (see 4.6.11)

But my desired output is

18.1.1.1.1 The requirements of this chapter apply to the following:

(1) New buildings or portions thereof used as health care occupancies (see 1.4.1)

(2) Additions made to, or used as, a health care occupancy (see 4.6.6 and 18.1.1.4)(2) and conform to the requirements for the specific occupancy in accordance with Chapters 12 through 17 and Chapters 20 through 42, as appropriate.

Exception: The requirement of 18.1.1.1.1 shall not apply to additions classified as occupancies other than health care that are separated from the health care occupancy in accordance with 18.1.2.1

(3) Alterations, modernizations, or renovations of existing health care occupancies (see 4.6.7 and 18.1.1.4)

(4) Existing buildings or portions thereof upon change of occupancy to a health care occupancy (see 4.6.11)

Here it break the line of (2) again of this value "(see 4.6.6 and 18.1.1.4) (2) " .how can i get this format?

Answer 1

在您的正则表达式中，尝试仅分割\\(\\d)\\ ，在它们前面有一个空格：

str = str.replace(/(\s\(\d+\)|exception\s*\:*)/gi, "<br /><br />$1&nbsp");

Answer 2

Look for something that isn't a closing paren before the number in parens. You have to fake it out on the exception part. I decided to find a non-alphabetic before the word "exception". That makes sure its a whole word, at least on the front. (Though, to be fair, I can't think of an English word that ends with "expression".)

Note how JavaScript numbers the matched strings by the ordering of the parens in the regular expression and not by the order of the parens as the matcher goes through finding things that match. So the parts that aren't matched (because of the or) still count in the $1, $2, $3 and $4.

str = str.replace(/([^)])(\(\d+\))|([^a-zA-Z])(exception\s*\:*)/gi, "$1$3<br /><br />$2$4&nbsp");

You can test Javascript regular expressions here: http://www.regexplanet.com/advanced/javascript/index.html

(That's what I did to get that expression working.)

Answer 3

您可以将(?:\\(\\d+\\))*合并到您的正则表达式中，除非我错过了您想要的东西？

Answer 4

Using

str = str.replace(/(\(\d+\)|exception\s*\:*)(\S)/gi, "<br /><br />$1&nbsp;$2");

It seems working: see http://jsbin.com/otuteh/1/edit