[英]Method duplicates output
Pretty new to sling and Java so I apologize in advance. 吊索和Java很新,所以我提前致歉。 But does anybody have any idea why when I'm at the root it's outputting my path twice?
但是有人知道为什么当我处于根源时会两次输出我的路径吗? It's odd that it only happens at the absolute root.
奇怪的是,它只发生在绝对根上。
public static String generateTest(Page page, Page rootPage, String bc) {
Page parent = page.getParent();
String bread = "";
bread += (parent != null) ? "<li><a href=" + parent.getPath() + ">" + parent.getTitle() + "</a>" : "";
bread += "<li>" + "<a href=" + page.getPath() + ">" + page.getTitle() + "</a></li>" + bc;
return (ifAtRoot(parent , rootPage)) ? breadcrumb : generateTest(parent, rootPage, bread);
}
public static boolean ifAtRoot(Page page, Page root) {
return (page == null || root.getPath() == page.getPath());
}
Any help is greatly appreciated! 任何帮助是极大的赞赏!
First, ifAtRoot()
will return true only if page
is null
because you cannot compare objects (including strings) using ==
. 首先,
ifAtRoot()
仅在page
为null
时才返回true,因为您不能使用==
比较对象(包括字符串)。 You should use .equals()
instead: 您应该改用
.equals()
:
public static boolean ifAtRoot(Page page, Page root) {
return (page == null || root.getPath().equals(page.getPath()));
}
In your case first call of ifAtRoot()
returned false
, so you called it second time recursively passing brend
that just has been created. 在您的情况下,第一次调用
ifAtRoot()
返回false
,因此您第二次调用它以递归方式传递刚创建的brend
。 The second call creates brend
again and appends bc
(that contains previously created brend) to it. 第二个调用再次创建
brend
,并向其附加bc
(包含先前创建的brend)。 The second call of ifAtRoot()
for your luck returns true. 如果需要,第二次调用
ifAtRoot()
返回true。 Otherwise you'd enter infinite recursion and finish with StackOverflowError
. 否则,您将输入无限递归并以
StackOverflowError
完成。
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