简体   繁体   English

使用isalpha()在文件中跳过了一行

[英]One line is being skipped in file with isalpha()

I am using isalpha() to determine if there are characters on the line and it is showing that the line "90 1 0" contains alphabetic characters. 我正在使用isalpha()确定行上是否有字符,并显示“ 90 1 0”行包含字母字符。

Here is the relevant code 这是相关的代码

bool digitTest(char *test, int arysize)
{
int i;
for (i =0; i<arysize; i++)
{
    if ((isalpha(test[i])) != 0){

        return 0;
    }

    if (i==arysize)
        return 1;
            i++;
}
return 1;
}

It is called here 叫这里

char buffer[4096] = {};

while(NULL!=fgets(buffer, sizeof(buffer), fp)){
    if (digitTest(buffer, 4096) == 0){

        printf ("contains alpha\n");
        continue;
    /*printing code if there is no alphabetic characters below, i do not believe it is  relevant*/

and this is output 这是输出

1
1
1
contains alpha 
contains alpha
contains alpha 
25123.90
54321.23
6

and input 和输入

1
1
1
89 23.5 not a number
90 1 0
-5.25 not a number 10000
25123.90 54321.23 6

The code has a few problems: 该代码有一些问题:

  • You shouldn't check all buffer. 您不应该检查所有缓冲区。 Check buffer until \\0 . 检查缓冲区,直到\\0为止。 because the output of fgets is a C-style string. 因为fgets的输出是C样式的字符串。

  • Second problem is an extra i++ in function digitTest . 第二个问题是在digitTest函数中有一个额外的i++ You should remove it. 您应该删除它。

  • You don't need arysize any more. 您不再需要arysize

Use this digitTest function instead 使用此digitTest函数代替

int digitTest(char *test)
{
  int i;
  for (i=0; test[i] && test[i] != '\n'; i++)
  {
     if (isalpha(test[i]) != 0)
        return 0;
  }
  return 1;
}

(maybe has minor bugs, I didn't test it) (也许有一些小错误,我没有测试过)

And call it like this: 并这样称呼它:

while( fgets(buffer, sizeof(buffer), fp) ) {
    if (!digitTest(buffer)) {
        printf ("contains alpha\n");
        continue;
    }
}

It Looks like you might be accessing locations in memory that contain characters, Change your code to 看来您可能正在访问包含字符的内存中的位置,将代码更改为

char buffer[4096] = {};
memset(buffer, 0, 4096);

while(NULL!=fgets(buffer, sizeof(buffer), fp)){
if (digitTest(buffer, strlen(buffer)) == 0){ //get actual length of buffer

    printf ("contains alpha\n");
    continue;

EDIT 编辑

In order to make your code not respond to either \\n or \\r do 为了使您的代码不响应\\n\\r

bool digitTest(char *test, int arysize)
{
int i;
for (i =0; i<arysize; i++)
{
    if( test[i] == '\r' || test[i] == '\n')
        return 1;
    if ((isalpha(test[i])) != 0){

        return 0;
    }

    if (i==arysize)
        return 1;

}
return 1;
}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM