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D3 JSON数据转换

[英]D3 JSON data conversion

I have this JSON data structure: 我有这个JSON数据结构:

[
    { "dep": "d1", "name": "name1", "size": "size1" },
    { "dep": "d1", "name": "name2", "size": "size2" },
    { "dep": "d2", "name": "name1", "size": "size3" },
    { "dep": "d2", "name": "name1", "size": "size4" }
]

and I want to convert it to a nested structure like this: 我想将它转换为嵌套结构,如下所示:

{
    "name": "root",
    "children": [
        { "name": "d1",
            "children": [
                { "dep": "d1", "name": "name1", "size": "size1" },
                { "dep": "d1", "name": "name2", "size": "size2" }
            ]
        },
        { "name": "d2",
            "children": [
                { "dep": "d2", "name": "name1", "size": "size3" },
                { "dep": "d2", "name": "name2", "size": "size4" }
            ]
        }
    ]
}

... and further using it to make the Reingold–Tilford Tree . ......并进一步用它来制作Reingold-Tilford树 Can anyone point me to the right direction, I'm pretty new to D3! 谁能指出我正确的方向,我对D3很新!

The strategy is to create a new empty data structure corresponding to what you want, and then fill it by going through the whole original dataset. 策略是创建一个与您想要的对应的新的空数据结构,然后通过遍历整个原始数据集来填充它。 Here is the code: 这是代码:

var data = [
    { "dep": "d1", "name": "name1", "size": "size1" },
    { "dep": "d1", "name": "name2", "size": "size2" },
    { "dep": "d2", "name": "name1", "size": "size3" },
    { "dep": "d2", "name": "name2", "size": "size4" }
]

var newData = {"name": "root", "children": {}}

data.forEach(function (d) {
    if (typeof newData.children[d.dep] !== 'undefined') {
        newData.children[d.dep].children.push(d)
    } else {
        newData.children[d.dep] = {"name": d.dep, "children": [d]}
    }
})
newData.children = Object.keys(newData.children).map(function (key) {
    return newData.children[key];
});

The assignment at the end is to transform the object into an array. 最后的赋值是将对象转换为数组。

Which gives the desired result for newData : 这为newData提供了所需的结果:

{
    "name": "root",
    "children": [
        { "name": "d1",
            "children": [
                { "dep": "d1", "name": "name1", "size": "size1" },
                { "dep": "d1", "name": "name2", "size": "size2" }
            ]
        },
        { "name": "d2",
            "children": [
                { "dep": "d2", "name": "name1", "size": "size3" },
                { "dep": "d2", "name": "name2", "size": "size4" }
            ]
        }
    ]
}

jsFiddle: http://jsfiddle.net/chrisJamesC/eB4jF/ jsFiddle: http //jsfiddle.net/chrisJamesC/eB4jF/

Note: This method does not work for nested structures. 注意:此方法不适用于嵌套结构。 It will be way harder to do this for nested structures but you can always use a recursive function. 对嵌套结构执行此操作会更加困难,但您始终可以使用递归函数。


EDIT: As suggested by @imarane in his answer, you can use the d3.nest() which is way better than my hand made solution. 编辑:正如@imarane在他的回答中所建议的,你可以使用d3.nest() ,它比我的手工解决方案更好。 You might thus accept his answer. 你可能会接受他的回答。 By playing with it, it even was really easy to have multiple levels of nest: 通过玩它,甚至很容易有多层嵌套:

var data = [
    { "dep": "d1", "name": "name1", "size": "size1" },
    { "dep": "d1", "name": "name2", "size": "size2" },
    { "dep": "d2", "name": "name1"},
    { "dep": "d2"}
]

var newData = {
    "key":"root", 
    "children": 
        d3.nest()
            .key(function(d){return d.dep})
            .key(function(d){return d.name})
            .key(function(d){return d.size})
            .entries(data)
}     

Which give: 哪个给:

{"key":"root","children":[
    {"key":"d1","values":[
        {"key":"name2","values":[
            {"dep":"d1","name":"name2","size":"size1"},
            {"dep":"d1","name":"name2","size":"size2"}
        ]}
    ]},
    {"key":"d2","values":[
        {"key":"name1","values":[
            {"dep":"d2","name":"name1"}
        ]},
        {"key":"undefined","values":[
            {"dep":"d2"}
        ]}
    ]}
]}

Which the following data structure (I hope better to understand the whole point): 其中以下数据结构(希望更好地了解整点):

var data = [
    { "dep": "d1", "name": "name2", "size": "size1" },
    { "dep": "d1", "name": "name2", "size": "size2" },
    { "dep": "d2", "name": "name1"},
    { "dep": "d2"}
]

JsFiddle: http://jsfiddle.net/chrisJamesC/eB4jF/2/ JsFiddle: http //jsfiddle.net/chrisJamesC/eB4jF/2/

More on Nest: http://bl.ocks.org/phoebebright/raw/3176159/ 更多关于Nest: http //bl.ocks.org/phoebebright/raw/3176159/

another option is to use the nest method built into D3.... 另一个选择是使用内置于D3的嵌套方法....

var nested = d3.nest()
.key(function(d,i){ return d.dep; })
.entries(data);

which outputs: 哪个输出:

 [
  {
    "key": "d1",
    "values": [
      {
        "dep": "d1",
        "name": "name1",
        "size": "size1"
      },
      {
        "dep": "d1",
        "name": "name2",
        "size": "size2"
      }
    ]
  },
  {
    "key": "d2",
    "values": [
      {
        "dep": "d2",
        "name": "name1",
        "size": "size3"
      },
      {
        "dep": "d2",
        "name": "name2",
        "size": "size4"
      }
    ]
  }
]

JsFiddle: http://jsfiddle.net/imrane/bSGrG/1/ JsFiddle: http//jsfiddle.net/imrane/bSGrG/1/

Hey guys I think I found a fairly simple solution. 嘿伙计们,我想我找到了一个相当简单的解决方案。 I accomplished a very nice nesting of a large dataset (400,000 rows) for a hierarchical bar chart in a very streamline way. 我以非常精简的方式为分层条形图完成了一个非常好的大数据集(400,000行)嵌套。 It utilizes the Underscore library and an additional function _.nest . 它利用了_.nest库和一个附加功能_.nest Simply download and include the two libraries necessary 只需下载并包含必要的两个库

src="underscore-min.js"
src="underscore.nest.js"

Then use the _.nest function to create your structure. 然后使用_.nest函数创建结构。 Here's my line: 这是我的路线:

var newdata = _.nest(data, ["Material", "StudyName"]);

"Material" and "StudyName" are the columns I want to group my structure to. "Material""StudyName"是我想要将结构分组的列。

There are other options to use this function if you need to accomplish more things but I will leave it like this 如果你需要完成更多的事情,还有其他选项可以使用这个功能,但我会这样做

Use this. 用这个。 U can check the output in the console of the browser if u need. 如果需要,你可以在浏览器的控制台中检查输出。

function reSortRoot(root, value_key) {
                //console.log("Calling");
                for ( var key in root) {
                    if (key == "key") {
                        root.name = root.key;
                        delete root.key;
                    }
                    if (key == "values") {
                        root.children = [];
                        for (item in root.values) {
                            root.children.push(reSortRoot(root.values[item],
                                    value_key));
                        }
                        delete root.values;
                    }
                    if (key == value_key) {
                        root.value = parseFloat("1");
                        delete root[value_key];
                    }
                }
                return root;
            } 

            var testdata=[
                          { "dep": "d1", "name": "name1", "size": "size1" },
                          { "dep": "d1", "name": "name2", "size": "size2" },
                          { "dep": "d2", "name": "name1", "size": "size3" },
                          { "dep": "d2", "name": "name1", "size": "size4" }
                      ];

            var testJson = d3.nest()
            .key(function(d)  { return d.dep; })
            .entries(testdata); 
             console.log(testJson);

            var testRoot={};
            testRoot.key = "Information";
            testRoot.values = testJson;
            testRoot = reSortRoot(testRoot, "name");

             console.log(testRoot);

Since d3-collection has been deprecated in favor of d3.array , we can use d3.groups to achieve what used to work with d3.nest : 由于d3-collection已被弃用以支持d3.array ,我们可以使用d3.groups来实现与d3.nest一起使用的d3.nest

var output = {
  "name": "root",
  "children": d3.groups(input, d => d.dep).map(([k, vs]) => ({ "name": k, "children": vs }))
};

For example: 例如:

 var input = [ { "dep": "d1", "name": "name1", "size": "size1" }, { "dep": "d1", "name": "name2", "size": "size2" }, { "dep": "d2", "name": "name1", "size": "size3" }, { "dep": "d2", "name": "name1", "size": "size4" } ]; var output = { "name": "root", "children": d3.groups(input, d => d.dep).map(([k, vs]) => ({ "name": k, "children": vs })) }; console.log(output); 
 <script src="https://d3js.org/d3-array.v2.min.js"></script> 

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