sql从DB2提取特殊字符

Question

Name = McDonald's | # 176 address lane

Name = KFC | 67 address lane

condition :

The special character (.,/-!@#$^&.....) with name and address should be printed.

So, the name McDonald's and # 176 address lane should be printed and the rests of the names and addresses without the special characters should be eliminated

Expected Output :

McDonald's # 176 address lane

Answer 1

Take a look at LIKE for comparison. It will allow you to use % (or another character) as a wild card for string comparison. If you need more help after looking in the manual, please explain what part you did not understand.

Answer 2

You can probably use TRANSLATE :

SELECT Name, Address FROM mytable WHERE Name <> TRANSLATE(Name,'                 ', '(.,/-!@#$^&.....)') OR Address <> TRANSLATE(Address,'                 ', '(.,/-!@#$^&.....)')

The second parameter for TRANSLATE() is a string consisting of all characters you want to trap. The first parameter is a string of blanks the same length as the second parameter.

If any characters are found in Name or Address that match any characters in the second string, a changed value will be used for the comparison. By comparing against the original values, you'll catch rows that have the special characters.