取一串字母并将其放入数组中

Question

I have a string, "ABCDEFG" and I want to make an array that would look like this:

array[0] = "A"
array[1] = "B"
array[2] = "C"
etc.

Do I have tokenize the original string, or is there some type of built in way to do this?

Thanks!

Answer 1

If you want to make an array of strings, you can do it with a loop:

const char *str = "ABCDEFG";
string letters[7];
for (int i = 0 ; i != strlen(str) ; i++) {
    // The constructor below cuts out a single letter from the literal:
    letters[i] = string(&str[i], &str[i+1]);
}

Here is a demo on ideone .

For std::string original string, use substr ( demo ):

for (int i = 0 ; i != str.size() ; i++) {
    letters[i] = str.substr(i, 1);
}