在MVC C＃中关闭html条件编译

Question

I wrote this function

 <script type="text/javascript">
    function saveDelivery() {
       alert("tttt")
       var model = @Html.Raw(Json.Encode(Model)); //errror
       $.ajax({

           type: 'POST',

           url: '@Url.Action("SaveDelivery", "Business")',
           contentType: 'application/json; charset=utf-8',
           data: JSON.serialize(model),
           success: function (result) {                                  
           },
           error: function (xhr, ajaxOptions, thrownError) {
               alert(xhr.status);
               alert(thrownError);
          }
      });

  }    

but there is error on

var model = @Html.Raw(Json.Encode(Model));

it says conditional compilation is turned off How to slove this?

Answer 1

You could use an Html Extension to output the script tags. This can help help with intellisense problems in Visual Studio also.

public static class Extensions
{
    public static IHtmlString BeginScript(this HtmlHelper htmlHelper)
    {
       return new HtmlString("<script type=\"text/javascript\">");
    }

    public static IHtmlString EndScript(this HtmlHelper htmlHelper)
    {
        return new HtmlString("</script>");
    }
}

And then in your view:

@Html.BeginScript()

// JavaScript...

var model = @Html.Raw(Json.Encode(Model));

// More JavaScript...

@Html.EndScript()

NOTE: You'll need to add the namespace of your extension class to the <system.web.webPages.razor> element in web.config (the one in the views folder)

Answer 2

There are two options:

1. Do not care, you are sure about your code (it is warning)
2. Do something like this: var model = '@Html.Raw(Json.Encode(Model)) ', but probably you will have to change it to: var model = JSON.parse('@Html.Raw(Json.Encode(Model))')

Answer 3

mvc 4 assembly reference missing for Json.Encode

first add system.web.helper refrence
then right click on this refrence property and change Copy Locaal=false to true and run your code with json.Encode