[英]Python Regular expression - Substitution
I have written a python code : 我写了一个python代码:
import re
url = "www.google.com";
line = "../../asyouwish.html"
num = re.sub(r'(\.\.\/)*', url, line)
print ("Final : ", num)
My intention is to replace ../ (any number of times) with the url value provided. 我的意图是用提供的url值替换../(任意次数)。 However I am not getting correct output.
但是我没有得到正确的输出。 My desired output is "www.google.com/asyouwish.html".
我想要的输出是“ www.google.com/asyouwish.html”。
What I get is : 我得到的是:
Final : www.google.comawww.google.comswww.google.comywww.google.comowww.google.
comuwww.google.comwwww.google.comiwww.google.comswww.google.comhwww.google.com.w
ww.google.comhwww.google.comtwww.google.commwww.google.comlwww.google.com
Can anyone help me as where I went wrong !!! 谁能帮我解决我的问题!!! Thanks.
谢谢。
*
means 0-or-more occurrences. *
表示0个或多个事件。 +
means 1-or-more. +
表示1或更大。 You want a match to have at least 1 occurrence of ../
. 您希望匹配项至少出现一次
../
。 So change the *
to +
: 因此将
*
更改为+
:
import re
url = "www.google.com/"
line = "../../asyouwish.html"
num = re.sub(r'([.]{2}/)+', url, line)
print ("Final : ", num)
yields 产量
('Final : ', 'www.google.com/asyouwish.html')
Since the re.sub
will remove 1-or-more '../'
, you'll need to add a forward-slash after url
. 由于
re.sub
将删除1个或多个'../'
,因此您需要在url
之后添加一个正斜杠。 Above, I've added the forward-slash to url
itself. 上方,我在
url
本身中添加了正斜杠。 If url
comes without the forward-slash, you can (as an alternative) add it with 如果
url
不带正斜杠,则可以(用另一种方法)添加
num = re.sub(r'([.]{2}/)+', url+'/', line)
When you match on 0-or-more occurrences, r'([.]{2}/)*'
, each and every location between the characters in line
matches the pattern, so you get a substitution at each interstice. 当您匹配0个或多个出现的字符
r'([.]{2}/)*'
, line
中字符之间的每个位置都与该模式匹配,因此在每个空隙处都会得到一个替换。
In [9]: x = 'www.google.comawww.google.comswww.google.comywww.google.comowww.google.comuwww.google.comwwww.google.comiwww.google.comswww.google.comhwww.google.com.www.google.comhwww.google.comtwww.google.commwww.google.comlwww.google.com'
In [13]: x.split('www.google.com')
Out[13]: ['', 'a', 's', 'y', 'o', 'u', 'w', 'i', 's', 'h', '.', 'h', 't', 'm', 'l', '']
use something like 使用类似
url = "www.google.com";
line = "../../asyouwish.html"
link_part = line.split("/")
final_url = url + "/" + link_part[-1]
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