球形模式以同时匹配两个日期

Question

I'm using glob in this format at the moment:

glob('/STORAGE/LOGFILES/*.*')

Within /STORAGE/LOGFILES, there are hundreds of text files that all begin with YYYY-MM-DD. I'd like to change the *.* in my pattern to instead only look at the current month and previous month:

glob('/STORAGE/LOGFILES/2013-04*')
glob('/STORAGE/LOGFILES/2013-03*')

What I can't seem to figure out is how to do this in a single statement. I think I've figured out how to do the current month:

glob('/STORAGE/LOGFILES/'.date("Y-m").'*')

but I'd like a way to combine it all into a single statement. Appreciate any help and thank you!

Answer 1

You can use GLOB_BRACE option like this:

$now = new DateTime();
$lastMonth = new DateTime('-1 month');
$monthList = $now->format('Y-m').','.$lastMonth->format('Y-m');
$pattern = '/STORAGE/LOGFILES/{'.$monthList.'}*';
glob($pattern, GLOB_BRACE);

Answer 2

try this code

glob('/STORAGE/LOGFILES/[0-9][0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9]*')

You can play with glob pattern : http://cowburn.info/2010/04/30/glob-patterns/ Have fun

Answer 3

It seems to me that is platform (or shell) depended.

The glob() function searches for all the pathnames matching pattern according to the rules used by the libc glob() function, which is similar to the rules used by common shells.

See this note: http://www.php.net/manual/en/function.glob.php#110340

<?php

$a = glob('/path/*{foo,bar}.dat',GLOB_BRACE);
print_r($a);

?>

Result : 
Array
(
    [0] => /path/file_foo.dat
    [1] => /path/file_foobar.dat
    [2] => /path/file_foobar.dat
)

Maybe you could try an '|' or sign as well?

Doesn't it support regex: http://www.php.net/manual/en/function.glob.php#88250 ?

Answer 4

怎么样

glob('/STORAGE/LOGFILES/'.date("Y").'-{'.date("m").','.date("m")-1.'}*',GLOB_BRACE)