[英]Cannot call method 'update' of undefined Cgridcview
$.fn.yiiGridView.update('sopodetail-grid'+itemcd);
this function it's not running. 此功能未运行。
It says Cannot call method 'update' of undefined
in console. 它说
Cannot call method 'update' of undefined
在控制台中Cannot call method 'update' of undefined
。
I have problem when inserting data via ajax gridview
not refreshing. 通过ajax
gridview
插入数据时,我没有刷新的问题。
I render multiple grid view with foreach looping, and make each of them unique id with concatenating item_cd
. 我使用foreach循环渲染多个网格视图,并通过串联
item_cd
使它们每个都具有唯一的ID。
function validateDetailForm()
{
var jForm = $('#sopodetail-form');
var data = jForm.serialize();
var itemcd = $('#cmbitemcd').val();
$.ajax({
type: 'POST',
url : jForm.attr('action'),
data: data,
dataType:'html',
success:function(data)
{
$(".info").animate({opacity: 1.0}, 3000).fadeOut("slow");
$.fn.yiiGridView.update('sopodetail-grid'+itemcd);
},
error: function(data) { // if error occured
alert('Error occured.please try again');
$('#detail-content').html(data);
},
});
}
this how i can render multiple gridview i concating the id... 这就是我可以渲染多个gridview我的ID ...
foreach($modelSoDet as $modelSoDetObj):
$this->widget('zii.widgets.CDetailView', array(
'data'=>$modelSoDetObj,
'attributes'=>array(
'item_cd',
'item.item_name',
'item.item_desc',
'qty',
'qty_purchased'
)
));
$modelSoPoDetail = new Sopodetail();
$modelSoPoDetail->unsetAttributes();
$modelSoPoDetail->so_cd = $modelSoDetObj->so_cd;
$modelSoPoDetail->item_cd = $modelSoDetObj->item_cd;
$gridid = 'sopodetail-grid'.$modelSoPoDetail->item_cd;
$this->widget('zii.widgets.grid.CGridView', array(
'dataProvider'=>$modelSoPoDetail->search(),
'summaryText' => '',
'id'=>$gridid,
'columns'=>array(
'type',
'po_cd',
'qty'
)
));
endforeach;
您应该简单地尝试使用正确的语法:
$('sopodetail-grid'+itemcd).yiiGridView('update');
$.param.querystring
is called from the yiiGridView.update
and is located in the jquery.ba-bbq.js
. $.param.querystring
从所谓yiiGridView.update
和位于jquery.ba-bbq.js
。
check your HTML source if you have the jquery.ba-bbq.js
included... 检查您的HTML源代码是否包含
jquery.ba-bbq.js
...
If the jquery.ba-bbq.js
is included then you may be recreating the jQuery object after jquery.ba-bbq.js
. 如果包括了
jquery.ba-bbq.js
,那么您可能在jquery.ba-bbq.js
之后重新创建jQuery对象。 Eg jQuery is loaded more than once.... 例如,jQuery已加载多次。
Source: http://www.yiiframework.com/forum/index.php/topic/9387-cgridview-update/ 资料来源: http : //www.yiiframework.com/forum/index.php/topic/9387-cgridview-update/
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