[英]How to update JList while adding or removing elements with using DefaultListModel()
i know this question asked many times before. 我知道这个问题以前问过很多次。 However, i spent on hours to research about a way to update a JList, and i couldn't handle with this issue.
但是,我花了几个小时来研究更新JList的方法,但我无法处理这个问题。 I'm trying to implement a JList which shows who is online or offline.(It holds JLabels i guess this is the only way for holding a string with an icon).
我正在尝试实现一个JList来显示谁在线或离线(它持有JLabels,我猜这是持有带有图标的字符串的唯一方法)。 I have my own
CellRenderer()
which is like; 我有自己的
CellRenderer()
,就像;
public class UserRenderer extends DefaultListCellRenderer {
@Override
public Component getListCellRendererComponent(JList list, Object value,int index, boolean isSelected, boolean hasFocus) {
if(value instanceof ClientObject){
final ClientObject clientObject = (ClientObject) value;
JLabel label = (JLabel) super.getListCellRendererComponent(list, clientObject.getNickName(), index, isSelected, hasFocus);
if(clientObject.isIsOnline()){
label.setIcon(iconArray[1]);
}
else{
label.setIcon(iconArray[0]);
}
return label;
}
else {
return super.getListCellRendererComponent(list, value, index, isSelected, hasFocus);
}
}
}
Moreover, i construct client's list whenever he/she gets connected to server with this way; 而且,只要他/她以这种方式连接到服务器,我就会构造客户的清单。
private void buildBuddyList(ClientObject tempClientObject){
if( tempClientObject.getBuddyList().size() > 0 ){
mainClient.setBuddyList(tempClientObject.getBuddyList());
for (Iterator<ClientObject> iter = mainClient.getBuddyList().iterator(); iter.hasNext();) {
ClientObject tempon = iter.next();
if(tempon.isIsOnline()){
model.addElement(tempon);
labelIconList.put(tempon, iconArray[1]);
}
else{
model.addElement(tempon);
labelIconList.put(tempon, iconArray[0]);
}
}
}
}
The trick which i use when a client changed his/her status (becomes online/offline) is i get rid off all elements with model.clear()
and start to construct the list again. 当客户更改其状态(变为在线/离线)时,我使用的技巧是使用
model.clear()
摆脱所有元素, model.clear()
再次开始构建列表。 Here is the code segment; 这是代码段;
if(tempClientObject.isStatusChanged()){
if(tempClientObject.isIsConnected()){
System.out.println(tempClientObject.getUserName() + " is ONLINE");
model.clear();
for (Iterator<Map.Entry<ClientObject,ImageIcon>> iter = labelIconList.entrySet().iterator(); iter.hasNext();) {
Map.Entry<ClientObject,ImageIcon> pairs = iter.next();
ClientObject changedOnlineStatusClient = (ClientObject) pairs.getKey();
if(changedOnlineStatusClient.getUserName().equals(tempClientObject.getUserName())){
changedOnlineStatusClient.setIsOnline(tempClientObject.isIsOnline());
}
model.addElement(changedOnlineStatusClient);
}
}
else{
System.out.println(tempClientObject.getUserName() + " is OFFLINE");
model.clear();
for (Iterator<Map.Entry<ClientObject,ImageIcon>> iter = labelIconList.entrySet().iterator(); iter.hasNext();) {
Map.Entry<ClientObject,ImageIcon> pairs = iter.next();
ClientObject changedOnlineStatusClient = (ClientObject) pairs.getKey();
if(changedOnlineStatusClient.getUserName().equalsIgnoreCase(tempClientObject.getUserName())){
changedOnlineStatusClient.setIsOnline(tempClientObject.isIsOnline());
}
model.addElement(changedOnlineStatusClient);
}
}
}
I can assure that logical system works fine.(I can check the actions if they are working properly on background). 我可以确保逻辑系统运行正常。(我可以检查操作是否在后台正常运行)。 Only the problem is sometimes when a client connected to server JList looks blank even though it adds elements into model.
唯一的问题是有时即使连接到服务器JList的客户端看起来空白,即使它向模型中添加了元素也是如此。 i will appreciate for every answer.
我会很感激每个答案。 And thanks anyway
还是谢谢你
only comment, not an answer
只评论,不回答
there no require for one dimensional JList
不需要一维
JList
if(value instanceof ClientObject){
because Object
from 因为
Object
从
getListCellRendererComponent(JList list, Object value, int index,
boolean isSelected, boolean hasFocus) {
returns the same value, then to test this value if == or equeals
... 返回相同的值,然后
if == or equeals
,则测试此值...
First of all thanks for all your replies. 首先感谢您的所有答复。 On the other hand, i corrected my issue with creating a new model whenever it has to be get updated.
另一方面,无论何时需要更新,我都会创建一个新模型来纠正我的问题。 So the code segment is like this;
所以代码段是这样的;
DefaultListModel tempModel = new DefaultListModel();
// add or remove elements from tempModel
buddyList.setModel( tempModel );
i'm not sure about if it is the only correct way but at least it works. 我不确定这是否是唯一正确的方法,但至少能奏效。
Call model.fireContentsChanged()
method. 调用
model.fireContentsChanged()
方法。
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