[英]Regex to Trim cobination of spaves and line breaks from a string
I've a string, and I want to trim all the leading and trailing combination of space and < br />. 我有一个字符串,我想修剪所有前导和尾随的空间组合和<br />。 If the string is
如果字符串是
"< br /> < br />< br />< br /> < br /> < br /> Hello < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br />
“<br /> <br /> <br /> <br /> <br /> <br /> <br /> <br /> <br /> <br />
"“
I must get Hello. 我必须得到你好。 I unsuccessfully tried:
我没试成功:
string = string.replace(/(<br \/>)+$| +$/g,'').replace(/^(<br \/>)+|^ +/g,'')
You could try this: 你可以试试这个:
> var string = "< br /> < br />< br />< br /> < br /> < br /> Hello < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br /> <br />";
> string.replace(/^(<\s*br\s*\/>|\s*)*|(<\s*br\s*\/>|\s)*$/gi, '');
"Hello"
You could try this. 你可以试试这个。 I think this should help you,
我认为这应该对你有帮助,
var a="< br /> < br />< br />< br /> < br /> <br /> Hello < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br /> < br />";
var b=a.replace(/< br \/>|\s/g,"");
alert(b);//Hello
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