如何使用Linq获取除List中第n个元素之外的所有元素

Question

Say I have a list of 10 items.

List<char> chars = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J'];

I need a new List containing all the elements in the List except n'th (say, 3rd item 'C' ). I don't want the original list to be altered since I need it later.

Another option is, I can clone the list and remove the item, but then all the items after the n'th has to be shifted up.

Is there a way to get the list using Linq?

Edit:

A character can occur multiple times in the List. I want only the occurance at 'n' to be removed.

Answer 1

当然，使用Where接受索引参数的重载 ：

var allBut3 = chars.Where((c, i) => i != 2);  // use 2 since Where() uses 0-based indexing

Answer 2

You can use Enumerable.Where method.

Filters a sequence of values based on a predicate.

List<char> chars = new List<char>(){'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J'};
var newlist = chars.Where(n => n != chars.ElementAtOrDefault(2));

Here is a DEMO .