将日期时间显示为MM / dd / yyyy HH：mm格式c＃

Question

In database datetime is being stored in MM-dd-yyyy HH:mm:ss fromat.
However, I want to display datetime in "MM/dd/yyyy HH:mm" format. I tried it by using String.Format().

txtCampaignStartDate.Text = String.Format("{0:MM/dd/yyyy 
                           HH:mm}",appCampaignModel.CampaignStartDateTime);

Here appCampaignModel.CampaignStartDateTime is DateTime object having value in format.

I want to display in format.

Can anyone help me for this?

Answer 1

The slashes in this format MM/dd/yyyy HH:mm mean: "replace me with the actual separator of the current culture". You have to use CultureInfo.InvariantCulture explicitely:

txtCampaignStartDate.Text = appCampaignModel.CampaignStartDateTime.ToString("MM/dd/yyyy HH:mm", CultureInfo.InvariantCulture);

The "/" Custom Format Specifier

In database datetime is being stored in MM-dd-yyyy HH:mm:ss fromat.

Don't store datetimes with a format which means that you store them as (n)varchar . Use datetime instead.

Answer 2

txtCampaignStartDate.Text = appCampaignModel.CampaignStartDateTime
                                         .ToString().Replace("-","/");

or

String.Format("{0:MM/dd/yyyy HH:mm}", dt);

Check : String Format for DateTime [C#]

or

String date = dt.ToString("MM/dd/yyyy HH:mm", DateTimeFormatInfo.InvariantInfo);

DateTime.ToString Method (String, IFormatProvider)

Answer 3

为什么不只是一个简单的替换？

txtCampaignStartDate.Text = BadString.Replace("-","/");

Answer 4

try using an added culture info:

CultureInfo ci = new CultureInfo("en-US");
txtCampaignStartDate.Text = 
    appCampaignModel.CampaignStartDateTime.ToString("MM/dd/yyyy HH:mm", ci);

ps the culture info used is an example.

Answer 5

To display your date in format you specified:

txtCampaignStartDate.Text = appCampaignModel.CampaignStartDateTime.ToString("g",DateTimeFormatInfo.InvariantInfo)

And for more date time formats you can go through this link.

Answer 6

既然你已经有了一个DateTime对象，只需按照你想要的方式对其进行ToString：

appCampaignModel.CampaignStartDateTime.ToString("MM/dd/yyyy HH:mm");