创建批处理文件以在Java中设置路径

Question

I have installed JDK 1.7.0_17 on my windows7 32 bit machine and created a batch file set java path but it doesn't work.

I have installed jdk under c:\\program files.... and need to run java from E: and created batch file under E:\\ as follows:

set path="C:\Program Files\Java\jdk1.7.0_17\bin";

I got the following exception whenever I run the .bat file.

PATH=C:\Windows\system32;C:\Windows;C:\Windows\System32\Wbem;C:\Windows\System32
\WindowsPowerShell\v1.0\

What is the mistake in my code?

Answer 1

尝试这个：

  path="C:\Program Files\Java\jdk1.7.0_17\bin";%path%

Answer 2

After this set path="C:\\Program Files\\Java\\jdk1.7.0_17\\bin"; add pause();

Answer 3

You mention some exception but I do not see any exception in your question.

When you execute the batch file then the PATH variable is set/changed only for that command session.

If you start new command session then you will not see the changed value.

What it is that you want to achieve by just setting the PATH?

What ever you want to run using java so all that in one batch file/session or set the PATH environment variable manually before running the java command