[英]Can I run PHP code in Javascript without using AJAX?
How to convert JavaScript variable to php variable without using of AJAX inside the JavaScript function. 如何在JavaScript函数内部不使用AJAX的情况下将JavaScript变量转换为php变量。
function getProduct(category)
{
document.galaxy.action = '<?php echo JRoute::_('index.php?option=com_virtuemart&view=category&virtuemart_category_id=11') ?>';
document.getElementById('galaxy').submit();
}
I need to convert js variable "category" to php variable. 我需要将js变量“类别”转换为php变量。
This is not posible. 这是不可能的 。
Javascipt is an client-side language, this means that its going to run on the computer of your visitor. Javascipt是一种客户端语言,这意味着它将在访问者的计算机上运行。
PHP is an server-side language, this means that is going to run on your server. PHP是一种服务器端语言,这意味着它将在您的服务器上运行。
You can't. 你不能 What happens when a site is viewed:
浏览网站时会发生什么:
When you want use a JavaScript variable with PHP, you have so send it back to the server in some way (AJAX). 如果要在PHP中使用JavaScript变量,则可以通过某种方式将其发送回服务器(AJAX)。
var DivVal=document.getElementById('ChkStatus');
//var InnerVal=DivVal.innerHTML;
var editRedirect='<?php echo $this->createUrl("Employee/Print"); ?>';
window.location=editRedirect;
As other people mentioned, you are misunderstanding the concepts a little. 正如其他人所提到的,您对概念有些误解。
If you want something from your JS sent along with the form to your PHP script you should put it in a form field. 如果您希望将JS中的某些内容与表单一起发送到PHP脚本,则应将其放在表单字段中。
in your form use a hidden value: 在您的表单中使用隐藏值:
<input type="hidden" id="categoryInput" name="category" />
in your JS: 在您的JS中:
//Before you submit do this..
document.getElementById('categoryInput').value = category;
in your PHP: 在您的PHP中:
$category = $_REQUEST['category'];
EDIT: 编辑:
Seems like you are asking for this: 好像您要这样:
document.galaxy.action = '<?php echo JRoute::_('index.php?option=com_virtuemart&view=category') ?>&virtuemart_category_id=' + category;
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