[英]Django cannot pass the value form to the constructor
I have tried everything, but I cannot pass the value form to the constructor of ContactCSVModel below: 我已经尝试了所有方法,但是无法将值形式传递给下面的ContactCSVModel的构造函数:
if request.method == 'POST':
form = ConfiguratorForm(data=request.POST)
# Try and import CSV
ContactCSVModel.import_data(data=file, form=form)
the the class... 上课...
class ContactCSVModel(CsvModel, form):
first_name = CharField()
last_name = CharField()
company = CharField()
mobile = CharField()
group = DjangoModelField(Group)
contact_owner = DjangoModelField(User)
that CsvModel is part of Django-adaptors CsvModel是Django适配器的一部分
class ContactCSVModel(CsvModel, form):
means that the ContactCSVModel
extends a class called form
. class ContactCSVModel(CsvModel, form):
表示ContactCSVModel
扩展了一个名为form
的类。 I think this is what you really intended: 我认为这是您真正想要的:
class ContactCSVModel(CsvModel):
# stüfe
def __init__(self, form):
# using the form for other stüfe.
# maybe self.form = form?
I think what you are trying to do is use the form
to pass data to the ContactCSVModel
and ConfiguratorForm
has the same fields? 我认为您正在尝试使用
form
将数据传递给ContactCSVModel
和ConfiguratorForm
具有相同的字段吗? If so, you should make the form into a ModelForm
如果是这样,则应将表单制作为
ModelForm
class ConfiguratorForm(ModelForm):
class Meta:
model = ContactCSVModel
Otherwise, I am completely lost with what you are attempting to do... 否则,我完全迷失了您的尝试...
For example, what is currently in ConfiguratorForm
and where did file
come from? 例如,
ConfiguratorForm
当前file
什么? file
来自何处?
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