如何在C ++中声明byte *（字节数组）？

Question

How to Declare byte* ( byte array ) in c++ and how to define as a parameter in function definition?

when I declare like below

Function Declaration:

int Analysis(byte* InputImage,int nHeight,int nWidth);

Getting error : "byte" undefined

Answer 1

There is no type byte in C++. You should use typedef before. Something like

typedef std::uint8_t byte;

in C++11, or

typedef unsigned char byte;

in C++03.

Answer 2

The C++ type representing a byte is unsigned char (or other sign flavour of char , but if you want it as plain bytes, unsigned is probably what you're after).

However, in modern C++, you shouldn't be using raw arrays. Use std::vector<unsigned char> if your array is runtime-size, or std::array<unsigned char, N> (C++11) if your array is of static size N . You can pass these to functions via (const) references, like this:

int Analysis(std::vector<unsigned char> &InputImage, int nHeight, int nWidth);

If Analysis does not modify the array or its elements, do this instead:

int Analysis(const std::vector<unsigned char> &InputImage, int nHeight, int nWidth);