如何将SELECT查询的结果分配给变量？

Question

Can't extract the value of the $row['PID'] from the query...

$result = mysqli_query($con,"SELECT * FROM posts WHERE PID=(SELECT max(PID) FROM posts)");

$row = mysql_fetch_array($result);

$id = $row['PID'];

I know how to print it out:

while($row = mysqli_fetch_array($result))
      {
      echo $row['PID'];
      }

But no idea how to assign it to a variable without having to print it out...

Answer 1

In the second line, you are using mysql_fetch_array instead of mysqli_fetch_array . I'm not sure if that has anything to do with the problem (not used to sqli).

Can you do a print_r of the $row variable?

Answer 2

Try changing

$row = mysql_fetch_array($result);

to

$row = mysqli_fetch_array($result);

Answer 3

Change this line:

$row = mysql_fetch_array($result);

to this:

$row = mysqli_fetch_row($result);

Fetching an array will grab a multi dimensional array, so you'd have to use $row[0]['pid'] I believe.