PHP-使用Stripos（）过滤字符串

Question

I have read all thread about how to filter a string for certain needles and I think stripos() is what will do the job, however, the function does not return true when for example the first needle is found as if it is filtering the haystack using only the second value of my array.

Example :

$String = 'IWantToSolveThisProblem!!';
$needle = array('want', 'solve');

foreach ($needle as $value) {

$res = stripos($String, $value,0);
if($res !==false){

echo 'found';
}
else {
echo 'not found'; }}

In the example above the output will echo 'Found' because both values are present in my string.

The problem is that it is only using the last value of my array to loop. If the first value is present within the String and not the second it will return as false. I dont want to run multiple if statements

Answer 1

$String = 'IWantToSolveThisProblem!!'; //you were missing this semicolon
$needle = array('want', 'solve'); //no spaces before the array (not needed, I just like nospaces :P)

foreach($needle as $value) {

$res = stripos($String, $value,0);
if($res !==false){

echo 'found';
}
else {
echo 'not found'; }}

This doesn't make sense now... It's not that it's only comparing the last element. It just isn't comparing the first. See this example...

$haystack = "string to be tested";
$needles  = array("string","to","pineapple","tested");
foreach($needles as $needle){
    if(stripos($haystack,$needle,0)){
        echo "The word \"$needle\" was found in the string \"$haystack\".";
    }
    else{
        echo "The word \"$needle\" was NOT found in the string \"$haystack\".";
    }
}

Expected Output:
The word "string" was found in the string "string to be tested".
The word "to" was found in the string "string to be tested".
The word "pineapple" was NOT found in the string "string to be tested".
The word "tested" was found in the string "string to be tested".

Actual Output:
The word "string" was NOT found in the string "string to be tested".
The word "to" was found in the string "string to be tested".
The word "pineapple" was NOT found in the string "string to be tested".
The word "tested" was found in the string "string to be tested".

It all makes sense now... From the docs:

"This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE. Please read the section on Booleans for more information. Use the === operator for testing the return value of this function."

So, changing if(stripos($haystack,$needle,0)) to if(stripos($haystack,$needle,0) !== False) fixes the logic.

$String = 'IWantToSolveThisProblem!!'; 
$needle = array('want', 'solve', 42); 

foreach($needle as $value) {

if(stripos($String, $value,0) !== FALSE){
    echo "found \"$value\" in \"$String \"";
}
else {
    echo "$value not found"; 
    }
}

Answer 2

You should do:

if(stripos($value,$array[0]) !== false){ //check for the first element 
   echo "found want";
}
if(stripos($value,$array[1]) !== false){ //check for the second element
   echo "found solve";
}

Answer 3

I tested with this code:

<?php
$str = "IWantToSolveThisProblem!";
$str2 = 'IWantAnAnswer';
$needles = array('want', 'solve');

foreach ($needles as $needle){
        $res = stripos($str2, $needle, 0);
        if ($res !== false){
                echo "$needle found\n";
        }
        else {
                echo "$needle not found\n";
        }
}
echo "\n";
?>

and it outputs:

$php testme.php

want found
solve not found

So it seems to work for me here... you might check for typos maybe..??!

Answer 4

<?php
$String = 'IWantToSolveThisProblem!!';
$needle = array('want', 'solve');

foreach ($needle as $value) {

$res = stripos($String, $value,0);
if($res !==false){

echo 'found';
}
else {
echo 'not found'; }}
?>

Output: foundfound

If you "convert" your foreach-loop to if statements it would be the same as:

if(stripos($String,$needle[0]) !== false){ //check for the first element 
   echo "found";
}
if(stripos($String,$needle[1]) !== false){ //check for the second element
   echo "found";
}

Output: foundfound

So the foreach - loop does several if-conditions (one for each element in the array)

Answer 5

I've interpreted your question as a search to find a function that returns true when all needles are present in the given haystack, and here's a function that does just that...

/**
 * Search the haystack for all of the given needles, returning true only if 
 * they are all present.
 * 
 * @param  string  $haystack  String to search
 * @param  array   $needles   Needles to look for
 * @return boolean            
 */
function stripos_array($haystack, array $needles)
{
    foreach ($needles as $needle)
    {
        if (stripos($haystack, $needle) === false) return false;
    }
    return true;
}

// Test the function

$string = 'IWantToSolveThisProblem!!';

$search = array('want', 'solve');
$found = stripos_array($string, $search);
echo $found ? 'found' : 'not found', "\n"; // found

$search = array('want', 'cheese');
$found = stripos_array($string, $search);
echo $found ? 'found' : 'not found', "\n"; // not found

$search = array('cheese', 'problem');
$found = stripos_array($string, $search);
echo $found ? 'found' : 'not found', "\n"; // not found

---

It would be trivial to change this function to return true if any of the needles are found, instead of all needles.

/**
 * Search the haystack for any of the given needles, returning true if any of
 * them are present.
 * 
 * @param  string  $haystack  String to search
 * @param  array   $needles   Needles to look for
 * @return boolean            
 */
function stripos_array($haystack, array $needles)
{
    foreach ($needles as $needle)
    {
        if (stripos($haystack, $needle) !== false) return true;
    }
    return false;
}

Answer 6

您将得到“未找到”，因为当$ value变为“ solve”时，在$String = 'IWantAnAnswer'.找不到该$String = 'IWantAnAnswer'.