在Linux中：打印以开头的日志文件的最后一行

Question

I am trying to have the output of a single OS command display the last line of a log file, that starts with a specific string.

So basically I have a log file that reads:

Tom 
Paul 
Tom 
Steve 
Anthony 
Tom

I want to type a command similar to this:

tail -1 /etc/logfile | grep Steve

and have output like this: Steve

Unfortunately, the output of tail -1 only shows the last line of the log file...IF it matches. I want it to search the log file, from the bottom to the top (most recent to oldest) and print the first entry that matches the "Starts with" or grep. Thank you. I tried a bunch of combinations of tail, sed, cat and less...but I may be just doing something small wrong and missing it.

Answer 1

If the log is small enough that you don't care to scan it entirely, then

grep Steve etc/logfile | tail -n 1

will do your job. If the file is really big, you don't want to grep it since it will impact performance, so I will suggest building a script that read the file in reverse and stops in the first occurrence.

Answer 2

Just do it the other way round grep Steve /etc/logfile | tail -l grep Steve /etc/logfile | tail -l

grep Steve /etc/logfile

Gets all the lines with Steve then

tail -1

Prints the last of those.