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我该如何修复这个strtok()调用

[英]How can I fix this strtok() call

I have a problem with strtok() - it does not return the input as expected. 我有strtok()的问题 - 它没有按预期返回输入。

void parse_input(const char *input,unsigned char *ctext, int mlen){
  char * str = strdup(input);
  char * pch = strtok(str,"-");

  while (pch != NULL)
  {

    ctext[mlen] = (int) pch;


    pch = strtok (NULL, "-");

    mlen++;

  }

On input like 1-2-3-4 I would want it to fill ctext with [1,2,3,4]. 在像1-2-3-4这样的输入上,我希望它用[1,2,3,4]填充ctext。 That doesn't work, however. 但是,这不起作用。 What am I doing wrong? 我究竟做错了什么? Any help appreciated. 任何帮助赞赏。

ctext[mlen] = (int) pch;

That stores the numeric value of the pointer, whereas you really want the character pointed to by the pointer. 它存储指针的数值,而你真的想要指针指向的字符。 Time to read a good article/book/tutorial on pointers. 是时候阅读关于指针的好文章/书籍/教程了。

ctext[mlen] = *pch;

is what you're looking for. 是你在找什么。

你想获得的第一个字节的字符pch -没有地址pch

ctext[mlen] = *pch;
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

void parse_input(const char *input,unsigned char *ctext[], int *mlen){
    char * str = strdup(input);
    char * pch = strtok(str,"-");

    while (pch != NULL){
        ctext[(*mlen)++] = (unsigned char*)pch;
        pch = strtok (NULL, "-");
    }
}

int main(void){
    unsigned char *ctext[16];
    int mlen=0;
    int i;

    parse_input("1-2-3-4", ctext, &mlen);
    printf("[ ");
    for(i=0;i<mlen;++i){
        printf("%s", ctext[i]);
        if(i<mlen -1)
            printf(", ");
    }
    printf(" ]\n");
    //free(ctext[0]);
    return 0;
}

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