加载页面后，selenium获取当前URL

Question

I'm using Selenium Webdriver in Java. I want to get the current url after clicking the "next" button to move from page 1 to page 2. Here's the code I have:

    WebDriver driver = new FirefoxDriver();
    String startURL = //a starting url;
    String currentURL = null;
    WebDriverWait wait = new WebDriverWait(driver, 10);

    foo(driver,startURL);

    /* go to next page */
    if(driver.findElement(By.xpath("//*[@id='someID']")).isDisplayed()){
        driver.findElement(By.xpath("//*[@id='someID']")).click();  
        driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);
        wait.until(ExpectedConditions.visibilityOfElementLocated(By.xpath("//*[@id='someID']")));
        currentURL = driver.getCurrentUrl();
        System.out.println(currentURL);
    }   

I have both the implicit and explicit wait calls to wait for the page to be fully loaded before I get the current url. However, it's still printing out the url for page 1 (it's expected to be the url for page 2).

Answer 1

Like you said since the xpath for the next button is the same on every page it won't work. It's working as coded in that it does wait for the element to be displayed but since it's already displayed then the implicit wait doesn't apply because it doesn't need to wait at all. Why don't you use the fact that the url changes since from your code it appears to change when the next button is clicked. I do C# but I guess in Java it would be something like:

WebDriver driver = new FirefoxDriver();
String startURL = //a starting url;
String currentURL = null;
WebDriverWait wait = new WebDriverWait(driver, 10);

foo(driver,startURL);

/* go to next page */
if(driver.findElement(By.xpath("//*[@id='someID']")).isDisplayed()){
    String previousURL = driver.getCurrentUrl();
    driver.findElement(By.xpath("//*[@id='someID']")).click();  
    driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);

    ExpectedCondition e = new ExpectedCondition<Boolean>() {
          public Boolean apply(WebDriver d) {
            return (d.getCurrentUrl() != previousURL);
          }
        };

    wait.until(e);
    currentURL = driver.getCurrentUrl();
    System.out.println(currentURL);
} 

Answer 2

Page 2 is in a new tab/window ? If it's this, use the code bellow :

try {

    String winHandleBefore = driver.getWindowHandle();

    for(String winHandle : driver.getWindowHandles()){
        driver.switchTo().window(winHandle);
        String act = driver.getCurrentUrl();
    }
    }catch(Exception e){
   System.out.println("fail");
    }

Answer 3

It's been a little while since I coded with selenium, but your code looks ok to me. One thing to note is that if the element is not found, but the timeout is passed, I think the code will continue to execute. So you can do something like this:

boolean exists = driver.findElements(By.xpath("//*[@id='someID']")).size() != 0

What does the above boolean return? And are you sure selenium actually navigates to the expected page? (That may sound like a silly question but are you actually watching the pages change... selenium can be run remotely you know...)