C#：如何将 TimeSpan 值转换为双精度值？

Question

How do I convert a TimeSpan value to a double in C#?

I mean I have this -08:15:00 and I want a double -08.15 .

Answer 1

Despite how ambiguous this question is, for future reference, Umar was probably the closest to answering the question, as it was displayed in the title.

To get a double from a TimeSpan object, you need to pick the most significant measurement, and get the total. As the Total<x> property, will return the appropriate full value, and the fractions of that value as a decimal.

So, if you want 8:15:00 , to a double - and the "8" represents Hours , then you'll want TimeSpan.TotalHours which will result in a value of 8.25.

If the "8" represents Minutes , then again, you'll use the appropriate property TimeSpan.TotalMinutes for the same result, and so on.

Answer 2

您可以使用TimeSpan.TotalMinutes （获取以整数和小数分钟表示的当前TimeSpan结构的值）或其他类似属性。

Answer 3

不要在家里重复这个！

double value = (timeSpan.Hours + timeSpan.Minutes / 100.0 + timeSpan.Seconds / 10000.0) * (timeSpan > TimeSpan.Zero ? 1 : -1);

Answer 4

In the case of operations with DateTime in its double format obtained with .ToOADate() , TimeSpan must be converted to double directly with .TotalDays since the unit (1.0) for DateTime is a day.

With a functional mindset:

public static class Extension
{
    public static double ToDouble(this TimeSpan o) => o.TotalDays;
}

Answer 5

您可以使用 string.format，然后像这样解析它：

   double.Parse(string.Format("-HH.mm"))