[英]How to actually initialize a 2d vector of objects from a class/constructor
so far, the only link that was close to answering the question was this: How do I initialize a stl vector of objects who themselves have non-trivial constructors? 到目前为止,最接近回答这个问题的唯一链接是: 我如何初始化本身具有非平凡构造函数的对象的stl向量?
However, I attempted to do that and I am still stumped on it. 但是,我尝试这样做,但仍然感到困惑。
The relevant code: 相关代码:
Edge 边缘
// Edge Class
class Edge{
public:
// std::string is used to avoid not a name type error
Edge (std::string, double);
double get_dist();
std::string get_color();
~Edge();
private:
std::string prv_color; // prv_ tags to indicate private
double prv_distance;
};
Edge::Edge (std::string color, double distance){
prv_color = color;
prv_distance = distance;
};
Graph 图形
// Graph Class
class Graph{
public:
Graph (double, double);
double get_dist_range();
~Graph();
private:
double prv_edge_density; // how many edges connected per node
double prv_dist_range; // start from 0 to max distance
std::vector < std::vector <Edge*> > nodes; // the proper set-up of
};
// Graph constructor
Graph::Graph (double density, double max_distance){
prv_edge_density = density;
prv_dist_range = max_distance;
nodes (50, std::vector <Edge*> (50)); // THIS LINE STUMPS ME MOST
};
As I attempted to initialize a vector of object pointers, I get this error from the following line: 当我尝试初始化对象指针的向量时,我从以下行得到此错误:
nodes (50, std::vector <Edge*> (50)); // Error at this line
error: no match for call to ‘(std::vector<std::vector<Edge*, std::allocator<Edge*> >,
std::allocator<std::vector<Edge*, std::allocator<Edge*> > > >)
(int, std::vector<Edge*, std::allocator<Edge*> >)’
I would like advice on this as soon as possible. 我希望尽快对此提出建议。
Note: Assume that I have used .cpp files and .h files to separate the code 注意:假设我已经使用.cpp文件和.h文件来分隔代码
You need to learn about initializer lists 您需要了解初始化器列表
// Graph constructor
Graph::Graph (double density, double max_distance) :
nodes (50, std::vector <Edge*> (50))
{
prv_edge_density = density;
prv_dist_range = max_distance;
}
Untested code. 未经测试的代码。
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