MySQL - 将行合并为一个

Question

I searched through various questions but I didn't find an answer. I have a MySQL table 'teams':

+--+----+------+
|id|name|active|
+--+----+------+
|1 |bla |1     |
|2 |blu |0     |
|3 |croc|1     |
|4 |bold|1     |
|5 |foo |1     |
|6 |bar |0     |
+--+----+------+

and a table 'data':

+----+-------+----+
|team|project|time|
+----+-------+----+
|2   |some   |1   |
|2   |some2  |5   |
|3   |one    |16  |
|3   |one2   |100 |
|5   |more   |2   |
|5   |more2  |60  |
+----+-------+----+

In PHP I'm querying the data like this:

SELECT t.name, t.active, d.time
FROM teams t
RIGHT JOIN data d ON (t.id = d.team)
ORDER BY t.id

Everything works find and my result looks like this:

+----+------+----+
|name|active|time|
+----+------+----+
|blu |0     |1   |
|blu |0     |5   |
|croc|1     |16  |
|croc|1     |100 |
|foo |1     |2   |
|foo |1     |60  |
+----+------+----+

...but I want that my result looks like this:

+----+------+---+---+
|name|active|t1 |t2 |
+----+------+---+---+
|blu |0     |1  |5  |
|croc|1     |16 |100|
|foo |1     |2  |60 |
+----+------+---+---+

So... How can I reach this? I hope I have not overlooked an already asked question... :(

Thank you very much!

EDIT: First, thank you all, but I forgot something... It is also possible that eg one2 does not exist...

Answer 1

try this

 SELECT t.name, t.active, 
 min(time) t1, max(time)t2
FROM teams t
RIGHT JOIN data d ON (t.id = d.team)
group by name
ORDER BY t.id

DEMO HERE

EDIT:

try this

   SELECT t.name, t.active, 
   min(time) t1, if  (  max(time) is not null and max(time) <> min(time) , max(time), null )t2
  FROM teams t
  RIGHT JOIN data d ON (t.id = d.team)
  group by name
  ORDER BY t.id

DEMO HERE

Answer 2

If there cold be at maximum two rows for each team, I would use something like this:

SELECT
  teams.name,
  teams.active,
  min(d1.time) t1,
  max(d2.time) t2
FROM
  teams INNER JOIN data d1
  ON teams.id=d1.team
  LEFT JOIN data d2
  ON teams.id=d2.team AND d1.time<d2.time
GROUP BY
  teams.name,
  teams.active