[英]mySQL - Using two JOINs in one query?
I am trying to use two JOIN statements in one query, 我正在尝试在一个查询中使用两个JOIN语句,
$sqlsorgu = mysql_query("SELECT *, COUNT(*), AVG(clicks), AVG(scrolls), AVG(spent)
FROM track where referid='".$memberr."' GROUP BY referer ORDER BY id desc limit 15
JOIN
(
select id, country, num, num*100/total pct
from (SELECT id,country, count(*) as num
FROM track GROUP BY country
ORDER BY num desc limit 5) x
join (select count(*) total from track) y
) tc on t.id = tc.id") or die(mysql_error());
but I am getting this error: 但我收到此错误:
You have an error in your SQL syntax; 您的SQL语法有误; check the manual that corresponds to your MySQL server version for the right syntax to use near 'JOIN ( select id, country, num, num*100/total pct from (SELECT id,country' at line 1
查看与您的MySQL服务器版本相对应的手册以获取正确的语法,以在第1行的(SELECT id,country)中选择“ JOIN(选择id,国家,num,num * 100 /总pct)
What is the correct way to use it ? 正确的使用方法是什么?
GROUP BY/ WHERE/ Order by come after join statements. 在联接语句之后使用GROUP BY / WHERE / Order by。 Try reording like:
尝试像这样进行协调:
"SELECT *, COUNT(*), AVG(clicks), AVG(scrolls), AVG(spent)
FROM track t
JOIN
(
select id, country, num, num*100/total pct
from (SELECT id,country, count(*) as num
FROM track GROUP BY country
ORDER BY num desc limit 5) x
join (select count(*) total from track) y
) tc on t.id = tc.id
where referid='".$memberr."'
GROUP BY referer
ORDER BY tc.id desc limit 15
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