[英]Implementing Selection Sort for Linked Lists
I am trying to implement a selection sort algorithm that will work with linked lists and will use iterators to scrool through them. 我正在尝试实现一个选择排序算法,该算法将与链表一起使用,并将使用迭代器来通过它们。 The selection sort algorithm is the following: for each element of the list except the last one(let's call it
K
), it will seek out the smallest on from the position we are currently on(so it will start from K until the last element). 选择排序算法如下:对于列表中除最后一个元素之外的每个元素(让我们称之为
K
),它将从我们当前所处的位置中寻找最小的元素(因此它将从K开始直到最后一个元素)。 After that it will swap K and the smallest element.
之后,它将
swap K and the smallest element.
I think that my mistake is in the first for loop; 我认为我的错误是在第一个for循环中; I am very unsure that
--a.end()
is the pre-last element. 我不确定
--a.end()
是前一个元素。 I get some output, though it is wrong. 我得到一些输出,虽然这是错误的。
#include <iostream>
#include <list>
using namespace std;
void sort_list(list<int>& a)
{
//from the first until the pre-last element
for(list<int> :: iterator itr = a.begin(); itr != (--a.end()); ++itr)
{
int smallest = *itr;
//get smallest element after current index
list<int> :: iterator itr2 =itr;
++itr2;
for(; itr2 != a.end(); ++itr2)
{
if (smallest > *itr2)
{
smallest = *itr2;
}
}
//swap smallest and current index
int tmp = *itr;
*itr = smallest;
smallest = tmp;
}
}
int main()
{
//create a list and some elements
list<int> listi;
listi.push_back(5);
listi.push_back(4);
listi.push_back(3);
listi.push_back(2);
listi.push_back(1);
// sort the list
sort_list(listi);
//print all of the elements
for(list<int> :: iterator itr = listi.begin(); itr != listi.end(); ++itr)
{
cout << *itr << endl;
}
return 0;
}
问题是你糟蹋itr
在初始化itr2
。
When you do itr2 = ++itr
you also change the value of itr
, so instead you should do something like 当你做
itr2 = ++itr
你也改变了itr
的值,所以你应该做类似的事情
list<int> :: iterator itr2 = itr;
for(++itr2; itr2 != a.end(); ++itr2) {
...
}
Furthermore, you have to keep a pointer to the smallest element, if you want to swap it later, like this: 此外,如果要稍后交换,则必须保留指向最小元素的指针,如下所示:
int* smallest = &(*itr);
This also requires some other changes, you can find a working example of your code here . 这还需要进行一些其他更改,您可以在此处找到代码的工作示例。
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