[英]How to subset dataframe by last characters of a string in R
R-user, R-用户,
I have this dataframe: 我有这个数据帧:
head(Niger_Meteo_98.11)
X.ID_punto MM.GG.AA T2m_max
1 1 01/01/98 303.235
2 2 01/01/99 303.356
3 3 01/01/00 303.477
4 4 01/01/01 303.604
5 5 01/01/02 303.759
6 6 01/01/03 303.915
and I need to get only values from year 2002. So, I should select, on column MM.GG.AA
, those rows that end with " /02
". 我只需要从2002年获得值。因此,我应该在MM.GG.AA
列中选择那些以“ /02
”结尾的行。 I didn't find anything online...any hints? 我没有在网上找到任何东西......任何提示? Thanks! 谢谢!
Use standard subsetting with grep
, like this: 使用grep
标准子集,如下所示:
x <- read.table(text=" X.ID_punto MM.GG.AA T2m_max
1 1 01/01/98 303.235
2 2 01/01/99 303.356
3 3 01/01/00 303.477
4 4 01/01/01 303.604
5 5 01/01/02 303.759
6 6 01/01/03 303.915", header=TRUE)
x[grep("/02$", x$MM.GG.AA), ]
X.ID_punto MM.GG.AA T2m_max
5 5 01/01/02 303.759
The grep
regular expression /02$
searches for string that end in /02
, since the $
indicates the end of the string. grep
正则表达式/02$
搜索以/02
结尾的字符串,因为$
表示字符串的结尾。
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