[英]Run a function after an Ajax call has completed
There is something happening that I don't know why is it happening. 我不知道为什么会发生某种事情。 I have this 3 functions:
我有这三个功能:
app.progress();
app.success();
app.normal();
All three change a status block in my application. 这三个都更改了我的应用程序中的状态块。 And I have this
$.post
in one of my other functions, let's say: 我在其他功能之一中有这个
$.post
,可以这样说:
app.set : function() {
...
}
In my set
function I want to update the status block like this: 在我的
set
函数中,我想更新状态块,如下所示:
app.set : function() {
app.progress();
$.post('ajax.php', function(){
// do stuffs
}).done({function(){
app.success();
setTimeout(app.normal(), '2000');
})
}
But somehow, I cannot see the app.success
, it skips to app.normal
, when I remove the app.normal
I can see the app.success
. 但是以某种方式,我看不到
app.success
,它跳到app.normal
,当我删除app.normal
我可以看到app.success
。
Why is that? 这是为什么?
You're calling app.normal
right away, as that is what happens when you add the parenthesis to a function, change this: 您正在立即调用
app.normal
,因为在将括号添加到函数时会发生以下情况:
setTimeout(app.normal(), '2000');
to 至
setTimeout(app.normal, 2000);
referencing the function instead of calling it. 引用函数而不是调用它。
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