[英]mysql: strange error 1111 invalid use of group by
Following is a query i am trying to run. 以下是我试图运行的查询。
select location_data.trip_code,sum(max(device_time)-min(device_time)) from location_data,trip_management
where location_data.source_id=3 and location_data.trip_code=trip_management.trip_code
group by location_data.trip_code
there are various trips identified by trip_code in both trip_managemnet and location_data tables.these trips are taken by a single uniquely identified user (source_id=)3. trip_managemnet和location_data表中的trip_code标识了各种行程。这些行程由单个唯一标识的用户(source_id =)3进行。 what i am trying to do here is to sum all the time differences for each trip and then convert it into hh:mm:ss using the sec_to_time function to display the total time it took user 3 to take all of his trips.
我在这里尝试做的是总结每次旅行的所有时间差异,然后使用sec_to_time函数将其转换为hh:mm:ss,以显示用户3完成所有旅行所花费的总时间。
the problem with above query is that it generates error 1111 as soon as i apply sum() over the difference of max and min device_time of each trip. 上面的查询的问题是,一旦我对每次旅行的最大和最小device_time的差异应用sum(),它就会生成错误1111。 i cant afford a subquery because this in itself is a subquery in a larger query.
我不能提供子查询,因为这本身就是一个更大的查询中的子查询。
I hope i explained the problem well. 我希望我能很好地解释这个问题。
The issue here is that you are attempting to apply an aggregate SUM()
over the aggregates MAX(),MIN()
, but in fact the two levels operate on different groups. 这里的问题是你试图在聚合
MAX(),MIN()
上应用聚合SUM()
MAX(),MIN()
,但实际上这两个级别在不同的组上运行。 The inner one groups over location_data.trip_code
, and the outer one groups over the result of that. 内部组合在
location_data.trip_code
,外部组合在其结果上。 You'll need to wrap it in a subquery: 你需要将它包装在子查询中:
SELECT
trip_code,
/* Outer query sums the inner aggregates */
SUM(max_time - min_time) AS time_sum
FROM (
SELECT
location_data.trip_code,
/* Inner aggregates return the max & min times only */
max(device_time) AS max_time,
min(device_time) AS min_time
FROM
location_data,
INNER JOIN trip_management ON location_data.trip_code = trip_management.trip_code
WHERE
location_data.source_id=3
GROUP BY location_data.trip_code
) first_group
GROUP BY trip_code
I've also replaced you implicit join with an explicit INNER JOIN
, which is the preferred syntax nowadays. 我还用一个显式的
INNER JOIN
替换了你的隐式连接,这是现在的首选语法。
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