尝试从Java中的Runtime对象执行exe时出错

Question

I am running windows 7 and have an exe file I am trying to run using the following command in Java:

File dir = new File("C:\\PATH\\TO\\DIR");
String[] cmdArray = {"file.exe"};

if(dir.exists()){
    for(String s : dir.list()){
        if(s.equals(cmdArray[0]))
            System.out.println("File exists!");
    }
}

Runtime.getRuntime().exec(cmdArray,null,dir);

The exec(...) command, however, gives me this error:

Cannot run program "file.exe" (in directory "C:\PATH\TO\DIR"): CreateProcess error=2, The system cannot find the file specified

The above code does print out "File Exists!" so the file is there and Java knows it is there. I dont know how this is possible.

Also, I need to use Runtime.getRuntime().exex(...). This call is actually inside another method that I am not suppose to change so alternative solutions will not work for me. Thanks in advance!

EDIT: I ran the file in a cmd window without admin privileges and got the following message:

Error in Opening Configuration File in Read Mode

So I assume I have permission issues. How would I change the permissions in order for me to be able to run it?

EDIT2:

I tried changing cmdArray to this:

String[] cmdArray = {"C:\\PATH\\TO\\DIR\\file.exe"};

and it worked like a charm. One question though. Why did this work but not the other way? I assumed that Runtime.exec() ran at a high level like so in a cmd wibndow:

pushd dir
cmdArray[0] cmdArray[1] cmdArray[2] ... cmdArray[length - 1]
popd dir

Is this the wrong assumption?

Answer 1

您在C驱动器中存在权限问题。通过在C驱动器中手动执行"file.exe"进行检查。更好的解决方案是将"file.exe"保留在C驱动器以外的其他位置并从那里执行。

Answer 2

Perhaps, You will need to include your directory to your path . You may take a look at this question and this tutorial