[英]MS Chart - How to put the X label on the left for a column series
I am currently working on this graph (sorry it's my first post, so with my reputation I can't post image directly) : 我目前正在处理这张图(很抱歉,这是我的第一篇文章,因此,以我的声誉,我无法直接发布图片):
For a giving hour, for example 10h, my Y value represents a number of requests between 10h and 11h. 对于一个给定的小时,例如10h,我的Y值表示10h和11h之间的请求数。
As you can see on my graph, the columns are centered on their X label. 正如您在我的图表上看到的那样,列位于其X标签的中心。 My question is quite simple, how could I put the label on the left of the column, so on my graph all the columns will be between two labels.
我的问题很简单,如何将标签放在列的左侧,因此在我的图形上所有列都将位于两个标签之间。
In resume, I am looking for a way to do this on every columns : 在简历中,我正在寻找一种在每一列上执行此操作的方法:
In case you need this, here are the pertinent lines of my code about this graph 如果您需要此,这是我的关于此图的代码的相关行
myAdapter.Fill(DailyData);
// Add points to the series
for (int i = 0; i < DailyData.Rows.Count; i++)
{
DataRow row = DailyData.Rows[i];
if (int.Parse(row["Hours"].ToString()) < 10)
{
DailyChart.Series["Series1"].Points.AddXY("0" + row["Hours"].ToString() + "h", row["RequestsNumber"].ToString());
}
else
{
DailyChart.Series["Series1"].Points.AddXY(row["Hours"].ToString() + "h", row["RequestsNumber"].ToString());
}
}
// Set series chart type
DailyChart.Series["Series1"].ChartType = SeriesChartType.Column;
DailyChart.Series["Series1"]["PointWidth"] = "1";
// Set X axis labels format
DailyChart.ChartAreas["ChartArea1"].AxisX.Interval = 1;
Have a good day! 祝你有美好的一天!
I know the WinFormsChartSample from Microsoft for MSChart has a file called HistogramHelper.vb
which if I recall correctly solves your problem. 我知道Microsoft为MSChart提供的WinFormsChartSample有一个名为
HistogramHelper.vb
的文件,如果我记得正确的话,可以解决您的问题。
I personally use a slightly modified version of this code, which I'll put here: 我个人使用了此代码的稍微修改后的版本,将在这里输入:
HistogramHelper.vb HistogramHelper.vb
Imports System
Imports System.Drawing
Imports System.Drawing.Drawing2D
Imports System.Windows.Forms.DataVisualization.Charting
Imports System.Collections
'--------------------------------------------------------------------------------------
'Code extracted from the WinFormsChartSample from Microsoft
'Modified to only use a single Series obj, instead of two with one of them hidden
'Also removed out the Auto Labels and % Axis
'--------------------------------------------------------------------------------------
''' <summary>
''' Helper class that creates a histogram chart. Histogram is a data
''' distribution chart which shows how many values, from the data series,
''' are inside each segment interval.
'''
''' You can define how many intervals you want to have using the SegmentIntervalNumber
''' field or the exact length of the interval using the SegmentIntervalWidth
''' field. Actual segment interval number can be slightly different due
''' to the automatic interval rounding.
''' </summary>
Public Class HistogramChartHelper
#Region "Fields"
''' <summary>
''' Number of class intervals the data range is devided in.
''' This property only has affect when "SegmentIntervalWidth" is
''' set to double.NaN.
''' </summary>
Public SegmentIntervalNumber As Integer = 20
''' <summary>
''' Histogram class interval width. Setting this value to "double.NaN"
''' will result in automatic width calculation based on the data range
''' and number of required interval specified in "SegmentIntervalNumber".
''' </summary>
Public SegmentIntervalWidth As Double = Double.NaN
''' <summary>
''' Indicates that percent frequency should be shown on the right axis
''' </summary>
Public ShowPercentOnSecondaryYAxis As Boolean = True
#End Region ' Fields
#Region "Methods"
''' <summary>
''' Creates a histogram chart.
''' </summary>
''' <param name="chartControl">Chart control reference.</param>
''' <param name="dataPoints">Original Data Series</param>
''' <param name="histogramSeriesName">Name of the histogram series.</param>
Public Function CreateHistogram(ByVal chartControl As Chart, ByVal dataPoints() As Double, ByVal histogramSeriesName As String) As Series
' Validate input
If chartControl Is Nothing Then
Debug.Print("Invalid chart control passed")
Return Nothing
End If
Dim aSeries As New Series
' Set new series chart type and other attributes
aSeries.ChartType = SeriesChartType.Column
aSeries.BorderColor = Color.Black
aSeries.BorderWidth = 1
aSeries.BorderDashStyle = ChartDashStyle.Solid
' Get data series minimum and maximum values
Dim minValue As Double = Double.MaxValue
Dim maxValue As Double = Double.MinValue
Dim pointCount As Integer = 0
For i As Integer = 0 To dataPoints.Length - 1
' Process only non-empty data points
If dataPoints(i) > maxValue Then
maxValue = dataPoints(i)
End If
If dataPoints(i) < minValue Then
minValue = dataPoints(i)
End If
pointCount += 1
Next
' Calculate interval width if it's not set
If Double.IsNaN(Me.SegmentIntervalWidth) Then
Me.SegmentIntervalWidth = (maxValue - minValue) / SegmentIntervalNumber
Me.SegmentIntervalWidth = RoundInterval(Me.SegmentIntervalWidth)
End If
' Round minimum and maximum values
minValue = Math.Floor(minValue / Me.SegmentIntervalWidth) * Me.SegmentIntervalWidth
maxValue = Math.Ceiling(maxValue / Me.SegmentIntervalWidth) * Me.SegmentIntervalWidth
' Create histogram series points
Dim currentPosition As Double = minValue
currentPosition = minValue
Do While currentPosition <= maxValue
' Count all points from data series that are in current interval
Dim count As Integer = 0
For i As Integer = 0 To dataPoints.Length - 1
Dim endPosition As Double = currentPosition + Me.SegmentIntervalWidth
If dataPoints(i) >= currentPosition AndAlso dataPoints(i) < endPosition Then
count += 1
' Last segment includes point values on both segment boundaries
ElseIf endPosition > maxValue Then
If dataPoints(i) >= currentPosition AndAlso dataPoints(i) <= endPosition Then
count += 1
End If
End If
Next
' Add data point into the histogram series
aSeries.Points.AddXY(currentPosition + Me.SegmentIntervalWidth / 2.0, count)
currentPosition += Me.SegmentIntervalWidth
Loop
' Adjust series attributes
'This is a "Custom Property" http://msdn.microsoft.com/en-us/library/dd456700.aspx
aSeries("PointWidth") = "1"
' Adjust chart area
Dim chartArea As ChartArea = chartControl.ChartAreas(0)
'chartArea.AxisY.Title = "Frequency"
chartArea.AxisX.Minimum = minValue
chartArea.AxisX.Maximum = maxValue
' Set axis interval based on the histogram class interval
' and do not allow more than 10 labels on the axis.
Dim axisInterval As Double = Me.SegmentIntervalWidth
Do While (maxValue - minValue) / axisInterval > 10.0
axisInterval *= 2.0
Loop
chartArea.AxisX.Interval = axisInterval
Return aSeries
End Function
''' <summary>
''' Helper method which rounds specified axsi interval.
''' </summary>
''' <param name="interval">Calculated axis interval.</param>
''' <returns>Rounded axis interval.</returns>
Friend Function RoundInterval(ByVal interval As Double) As Double
' If the interval is zero return error
If interval = 0.0 Then
Throw (New ArgumentOutOfRangeException("interval", "Interval can not be zero."))
End If
' If the real interval is > 1.0
Dim step_Renamed As Double = -1
Dim tempValue As Double = interval
Do While tempValue > 1.0
step_Renamed += 1
tempValue = tempValue / 10.0
If step_Renamed > 1000 Then
Throw (New InvalidOperationException("Auto interval error due to invalid point values or axis minimum/maximum."))
End If
Loop
' If the real interval is < 1.0
tempValue = interval
If tempValue < 1.0 Then
step_Renamed = 0
End If
Do While tempValue < 1.0
step_Renamed -= 1
tempValue = tempValue * 10.0
If step_Renamed < -1000 Then
Throw (New InvalidOperationException("Auto interval error due to invalid point values or axis minimum/maximum."))
End If
Loop
Dim tempDiff As Double = interval / Math.Pow(10.0, step_Renamed)
If tempDiff < 3.0 Then
tempDiff = 2.0
ElseIf tempDiff < 7.0 Then
tempDiff = 5.0
Else
tempDiff = 10.0
End If
' Make a correction of the real interval
Return tempDiff * Math.Pow(10.0, step_Renamed)
End Function
#End Region ' Methods
End Class
I then have a Helper function to generate histograms: 然后,我有了一个Helper函数来生成直方图:
Public Function hist(ByVal x As Double(), Optional ByVal bins As Integer = 10) As System.Windows.Forms.DataVisualization.Charting.Series
' HistogramChartHelper is a helper class found in the samples Utilities folder.
Dim histogramHelper As New HistogramChartHelper()
' Specify number of segment intervals
histogramHelper.SegmentIntervalNumber = bins
' Create histogram series
Dim newSeries As Series = histogramHelper.CreateHistogram(gca(), x, "Histogram")
gca().ChartAreas(0).AxisX.IsLogarithmic = False
gca().ChartAreas(0).AxisY.IsLogarithmic = False
gca().Series.Add(newSeries)
gcf().DoRefresh()
Return newSeries
End Function
And trying to generate a Histogram similar to yours: hist({8,8,8,8,8,9,9,9,9,9,9,9,9,9,10,10,10,10,10,10,10,10,10,11,11,11,11,11,11,11,11,11,11,11,12,12,12,12,12,13,13,14,14,14,14,14,14,14,14,14,14,14,14,15,15,15,15,15,15,15,15,15,16,16,16,16,16,16,16,16,17,17,17,17,17,17,17,17,18,18})
并尝试生成类似于您的直方图:
hist({8,8,8,8,8,9,9,9,9,9,9,9,9,9,10,10,10,10,10,10,10,10,10,11,11,11,11,11,11,11,11,11,11,11,12,12,12,12,12,13,13,14,14,14,14,14,14,14,14,14,14,14,14,15,15,15,15,15,15,15,15,15,16,16,16,16,16,16,16,16,17,17,17,17,17,17,17,17,18,18})
I get: 我得到:
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.