如何从 ArrayBuffer 中获取二进制字符串？

Question

What is the way to obtain binary string from ArrayBuffer in JavaScript?

I don't want to encode the bytes, just get the binary representation as String.

Thanks in advance!

Answer 1

The following code will consistently convert an ArrayBuffer to a String and back again without losing or adding any additional bytes.

function ArrayBufferToString(buffer) {
    return BinaryToString(String.fromCharCode.apply(null, Array.prototype.slice.apply(new Uint8Array(buffer))));
}

function StringToArrayBuffer(string) {
    return StringToUint8Array(string).buffer;
}

function BinaryToString(binary) {
    var error;

    try {
        return decodeURIComponent(escape(binary));
    } catch (_error) {
        error = _error;
        if (error instanceof URIError) {
            return binary;
        } else {
            throw error;
        }
    }
}

function StringToBinary(string) {
    var chars, code, i, isUCS2, len, _i;

    len = string.length;
    chars = [];
    isUCS2 = false;
    for (i = _i = 0; 0 <= len ? _i < len : _i > len; i = 0 <= len ? ++_i : --_i) {
        code = String.prototype.charCodeAt.call(string, i);
        if (code > 255) {
            isUCS2 = true;
            chars = null;
            break;
        } else {
            chars.push(code);
        }
    }
    if (isUCS2 === true) {
        return unescape(encodeURIComponent(string));
    } else {
        return String.fromCharCode.apply(null, Array.prototype.slice.apply(chars));
    }
}

function StringToUint8Array(string) {
    var binary, binLen, buffer, chars, i, _i;
    binary = StringToBinary(string);
    binLen = binary.length;
    buffer = new ArrayBuffer(binLen);
    chars  = new Uint8Array(buffer);
    for (i = _i = 0; 0 <= binLen ? _i < binLen : _i > binLen; i = 0 <= binLen ? ++_i : --_i) {
        chars[i] = String.prototype.charCodeAt.call(binary, i);
    }
    return chars;
}

I tested it by round-tripping the following values in this jsfiddle: http://jsfiddle.net/potatosalad/jrdLV/

(String) "abc" -> (ArrayBuffer) -> (String) "abc"
(String) "aΩc" -> (ArrayBuffer) -> (String) "aΩc"
(Uint8Array) [0,1,255] -> (ArrayBuffer) -> (String) -> (Uint8Array) [0,1,255]
(Uint16Array) [0,1,256,65535] -> (ArrayBuffer) -> (String) -> (Uint16Array) [0,1,256,65535]
(Uint32Array) [0,1,256,65536,4294967295] -> (ArrayBuffer) -> (String) -> (Uint32Array) [0,1,256,65536,4294967295]

Answer 2

This has been made much simpler by additions to JavaScript in recent years – here's a one-line method to convert a Uint8Array into a binary-encoded string:

const toBinString = (bytes) =>
  bytes.reduce((str, byte) => str + byte.toString(2).padStart(8, '0'), '');

Example:

console.log(toBinString(Uint8Array.from([42, 100, 255, 0])))
// => '00101010011001001111111100000000'

If you're starting with an ArrayBuffer, create a Uint8Array "view" of the buffer to pass into this method:

const view = new Uint8Array(myArrayBuffer);
console.log(toBinString(view));

Source: the Libauth library ( binToBinString method )

Answer 3

This will give you a binary string from a typed array

var bitsPerByte = 8;
var array = new Uint8Array([0, 50, 100, 170, 200, 255]);
var string = "";

function repeat(str, num) {
    if (str.length === 0 || num <= 1) {
        if (num === 1) {
            return str;
        }

        return '';
    }

    var result = '',
        pattern = str;

    while (num > 0) {
        if (num & 1) {
            result += pattern;
        }

        num >>= 1;
        pattern += pattern;
    }

    return result;
}

function lpad(obj, str, num) {
    return repeat(str, num - obj.length) + obj;
}

Array.prototype.forEach.call(array, function (element) {
    string += lpad(element.toString(2), "0", bitsPerByte);
});

console.log(string);

Output is

000000000011001001100100101010101100100011111111

On jsfiddle

Or perhaps you are asking about this?

function ab2str(buf) {
    return String.fromCharCode.apply(null, new Uint16Array(buf));
}

Note: that using apply in this manner means that you can hit the argument limitation (some 16000 elements or so), and then you will have to loop through the array elements instead.

On html5rocks

Answer 4

I realize this is a very old question, but I wanted to add one more possible case/solution since I landed on this from a search:

I wanted an async/await version of FileReader.readAsBinaryString() because I am a capricious person and the callback interface annoyed me:

// Suppose `file` exists

let fr = new FileReader()
let string1

fr.onload = ({ target: { result }}) => string1 = result
fr.readAsBinaryString(file)

console.log(string1)

Additionally, MDN says that FileReader.readAsBinaryString() only exists for backward compatibility, and FileReader.readAsArrayBuffer() is recommended instead .

There are new methods available on Blob / File that give you text , ArrayBuffer s, and stream s, but no binary strings. Heeding MDN's advice, I figured we could go from ArrayBuffer to binary string using the new methods, and indeed we can:

// Again, suppose `file` exists

let ab, bufferToString, string2

bufferToString = (buffer) => {
    const bytes = new Uint8Array(buffer)
    return bytes.reduce((string, byte) => (string + String.fromCharCode(byte)), "")
}

ab = await file.arrayBuffer()
string2 = bufferToString(ab)

console.log(string2)

Assuming this is done in the same browser console:

string1 === string2 // true

Whether this is intelligence or stupidity is left to the reader.

Answer 5

function string2Bin(s) {
  var b = new Array();
  var last = s.length;
  for (var i = 0; i < last; i++) {
    var d = s.charCodeAt(i);
    if (d < 128)
      b[i] = dec2Bin(d);
    else {
      var c = s.charAt(i);
      alert(c + ' is NOT an ASCII character');
      b[i] = -1;
    }
  }
  return b;
}

function dec2Bin(d) {
  var b = '';
  for (var i = 0; i < 8; i++) {
    b = (d%2) + b;
    d = Math.floor(d/2);
  }
  return b;
}