Python将ddmmyy格式转换为有效日期

Question

I was trying to convert a date string to a valid date python format, but I got a erroneous date:

>from datetime import datetime
>mydate = '300413' # is 2013-04-30
>print datetime.strptime(mydate,'%d%m%Y')
>0413-02-01 00:00:00

How can I parse to a valid date, this date string?

Answer 1

As listed in the documentation , %Y is the code for a four-digit year. You should be using the code for a two-digit year, %y .

Answer 2

If you read strptime() and strftime() Behavior in the docs, %Y means:

Year with century as a decimal number [0001,9999]

But you're giving it a 2-digit year, with no century.

That's supposed to raise a ValueError . For example, if you try it with 2.5.6, 2.7.2, 3.2.1, or 3.3.0, you get this:

ValueError: time data '300413' does not match format '%d%m%Y'

But, thanks to a bug in older versions of Python, you might get garbage instead.

If you want a 2-digit year, use %y , when means:

Year without century as a decimal number [00,99].

Answer 3

try:

print datetime.strptime('300413','%d%m%y')
2013-04-30 00:00:00

only change '%Y' with '%y'