用PHP插入MySQL选择查询，空变量？

Question

Here's the query I'm trying to insert into a table in MYSQL

$query1 = "SELECT close FROM stocks WHERE the_date = '$the_date' AND ticker = '$ticker' ";
$result1 = mysql_query($query1) or die("Query failed : " . mysql_error());

I managed to print it out like this:

while($price = mysql_fetch_assoc($result1)){
  echo "Price: ".$price['close']."<br /></h2>";
     }

And I tried inserting with this:

$query3 = "INSERT INTO transactions (trans_ID,the_date,client_ID,ticker,shares,price,buy)
           VALUES (\"$trans_ID\",\"$the_date\",client_ID,\"$ticker\", 
            $shares,$price,$buy)";

But the error message on the page said this: "Query failed : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1)' at line 3" which is weird cause that's just where my html/head tags are.

So the I tried to do this:

var_dump($price);

and got this: bool(false)

so how do i make it so I can insert $price?? i looked up some stuff about inserting arrays, implodes, serializing, but I can't seem to get it to work?

thanks!

Answer 1

Your query should be like

$query3 = "INSERT INTO transactions (trans_ID,the_date,client_ID,ticker,shares,price,buy) VALUES ('$trans_ID','$the_date','$client_ID','$ticker', '$shares','$price','$buy')";

But also do'nt forget to use mysql_real_escape_string on all those variables in query.