从另一个python运行脚本

Question

I just want to have some ideas to know how to do that...

I have a python script that parses log files, the log name I give it as an argument so that when i want to run the script it's like that.. ( python myscript.py LOGNAME ) what I'd like to do is to have two scripts one that contains the functions and another that has only the main function so i don't know how to be able to give the argument when i run it from the second script.

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here's my second script's code:

import sys
import os 

path = "/myscript.py"
sys.path.append(os.path.abspath(path))
import myscript 

mainFunction()

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the error i have is:

script, name = argv 
valueError: need more than 1 value to unpack

Answer 1

Python (just as most languages) will share parameters across imports and includes. Meaning that if you do:

python mysecondscript.py heeey that will flow down into myscript.py as well. So, check your arguments that you pass.

Script one

myscript = __import__('myscript')
myscript.mainfunction()

script two

import sys
def mainfunction():
    print sys.argv

And do:

python script_one.py parameter

You should get:

["script_one.py", "parameter"]

Answer 2

You have several ways of doing it.

>>> execfile('filename.py')

Check the following link:

How to execute a file within the python interpreter?