使用DOS批处理，读取管道分隔文件中的第二行，并从第三列中提取日期

Question

I need to extract a date from a text file. File is in pipe delimited format. It has series of columns which might or might not have value. I need a date from the 3rd column in second row. After that, write that date in a new file. How to do that?

THANKS!!!

Answer 1

Something like this in a batch file?

for /f "skip=1 tokens=3 delims=|" %%G IN (%1) DO (echo %%G > %2)

Skips the first line and outputs the 3rd token in a pipe delimited file. File is provided as the first argument (%1) and then it is echo'ed.