Android：如何检查wifi是否经过身份验证

Question

My application is using wifi manager in android, but I am facing an error in a situation the situation is::WIFI is turned on but it is not authenticated(with our company wifi user name and password)at that time my application is force closing,

code I am using is

try{
    if (connectivityManager != null && 
       (connectivityManager.getNetworkInfo(1).getState() == NetworkInfo.State.CONNECTED) ||
       (connectivityManager.getNetworkInfo(0).getState() == NetworkInfo.State.CONNECTED))
    { 
        //You are connected, do something online.
        return true;
    }
    else if (connectivityManager.getNetworkInfo(0).getState() == NetworkInfo.State.DISCONNECTED ||  
             connectivityManager.getNetworkInfo(1).getState() == NetworkInfo.State.DISCONNECTED ) 
    {             
        //Not connected.        
        //Toast.makeText(getApplicationContext(), "You must be connected to the internet", Toast.LENGTH_LONG).show();
        loginTask.myPublishProgress("You must be connected to the internet");
        return false; 
    }   
    }
catch(NullPointerException ae)
   {
        ae.printStackTrace();
        loginTask.myPublishProgress("You must be connected to the internet");

   }

Answer 1

Use SupplicantState

SupplicantState supState; 
wifiManager = (WifiManager) getSystemService(Context.WIFI_SERVICE);
WifiInfo wifiInfo = wifiManager.getConnectionInfo();
supState = wifiInfo.getSupplicantState();

See this answer in stackoverflow

If COMPLETED - All authentication completed.

Answer 2

Hi check the below answers:

How to detect when WIFI Connection has been established in Android?

How do I see if Wi-Fi is connected on Android?

Answer 3

Don't use

conectivityManager.getNetworkInfo(0) and getNetworkInfo(1).

Instead of that use

For WiFi

NetworkInfo conectivityManager = connectivity.getNetworkInfo(ConnectivityManager.TYPE_WIFI);

For mobile networks(3g)

NetworkInfo conectivityManager = connectivity.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);

Cause on Jelly Beans will make trouble hardcoding values like that.