Solaris：gdb a.out>运行>是否打开子外壳？

Question

Haven't found anything about this.

Trying to learn gdb and I get the feeling I'm doing something wrong.

I compile the c program with gcc -g program.c -o a.out

then use the command gdb a.out followed with run and this opens a subshell after warning me that it's running. If I type a.out as a command, then ctrl+d I'll drop back to gdb and get whatever message it wanted to throw at me. Without running the a.out after dropping out of the subshell, gdb acts like I didn't do anything at all.

All the tutorials I've seen shows that run within gdb will run the loaded program. Googling hasn't found me anything.

Setting breakpoints seems to be ignored as well.

What I doing wrong?

Answer 1

I'm ridiculous.

The default shell is csh on our unix server. In my .cshrc I have an exec bash at the end of .cshrc to drop csh and load bash. The gdb output is in csh, and it's causing bash to load.

/derp