如果然后在java中使用正则表达式条件

Question

I have a pattern which goes like this

String1 :"String2",

i have to validate this pattern. here if u see there are two cases, the somestring1 can contain special characters if it is given within double quotes.

eg: "xxxx-xxx" :"yyyyyyyy",--------> is valid
but  xxxx-xxx  :"yyyyyyyy",--------> is not valid
    "xxxx-xxx  :"yyyyyyyy",--------> is not valid

So i need to create a regex which will check whether the double quotes is closed properly if it is present in String1.

Answer 1

Short answer: Regex doesn't work like that.

What you can do however, is to use two separate patterns to validate:

\"[^\"]+?\" :.*

To check the one that can contain special characters, and:

[a-zA-Z]+? :.*

To check the one that can't

EDIT:

Thinking some more about it, you could combine the two patterns above like so:

^(\"[^\"]+?\"|[a-zA-Z]+?) :.*$

Which will match something :"something" and "some-thing" :"something" but not "some-thing : "something" or some-thing : "something" . Assuming that the string only contains the given text.

Answer 2

如果我理解你的问题，这个简单的正则表达式应该有效

\"string1\" :\"string2\"

Answer 3

Maybe something like this?

(?<normalString>^[a-zA-Z]+$)|(?<specialString>^".*?"$)

This will capture only az characters and put them in the "normalString" group, or if there's an string within quotation marks, capture that and put it in the "specialString" group.