为什么这个匹配数字的sed命令不起作用？

Question

My command is like this:

echo "12 cats" | sed 's/[0-9]+/Number/g'

(I'm using the sed in vanilla Mac)

I expect the result to be:

Number cats

However, the real result is:

12 cats

Does anyone have ideas about this? Thanks!

Answer 1

+必须被反击以获得其特殊含义。

echo "12 cats" | sed 's/[0-9]\+/Number/g'

Answer 2

Expanding the + modifier works for me:

echo "12 cats" | sed 's/[0-9][0-9]*/Number/g'

Also, the -E switch would make the + modifier work, see choroba's answer.

Answer 3

使用perl，这将适用于unix或linux。

echo "12 cats" | perl -pe 's/\d+/Number/g'

Answer 4

In a very mystic way that is not explained (at least in resources I have so far..), You should check up the next terms:

globbing (in the context of bash), regex, extended regex

For your question it seems that the expr' you gave to sed is a regex or extended regex....so by a tutorial I read you should insert also the -r before your actual command in sed...

echo "12 cats" | sed -r 's/[0-9]+/Number/g'

Works for me in an Ubuntu 16.04 , bash.