[英]Sed command giving unexpected result
Below is the shell script I am trying to find the meaning. 下面是我试图找到含义的shell脚本。
sed 's/19984 $/98400 /' | sed 's/19992 $/99200 /'
I expect 19984 $ will get replaced with 98400 and this string will be passed to next sed command which replace 19992 $ with 99200 . 我希望将19984 $替换为98400,并将此字符串传递给下一个sed命令,该命令将19992 $替换为99200。
But when I executed the script below with sample input 但是当我使用示例输入执行以下脚本时
echo "19984 $ need to be replaced with 98400 "| sed 's/19984 $/98400 /' | sed 's/19992 $/99200 /'
I get the same string 我得到相同的字符串
"19984 $ need to be replaced with 98400"
I hope something I am missing here. 我希望我在这里想念的东西。 Please help me.
请帮我。 I am new to shell scripts.
我是Shell脚本的新手。 Thanks in advance!
提前致谢!
For sed, $
is a reserved character to you have to escape it ( \\$
) to be parsed properly: 对于sed,
$
是保留字符,您必须对其进行转义( \\$
)才能正确解析:
$ echo "19984 $ need to be replaced with 98400 "| sed 's/19984 \$/98400 /'
98400 need to be replaced with 98400
All together: 全部一起:
$ echo "19984 $ need to be replaced with 98400 "| sed 's/19984 \$/98400 /' | sed 's/19992 \$/99200 /'
98400 need to be replaced with 98400
So you need to keep it like it is. 因此,您需要保持原样。
$
can mean a lot of things: $
可能意味着很多事情:
- a normal character. -正常角色。
- end of line. - 行结束。
- name of a variable. -变量名。
The way you got the code it means the second case: end of line: 获得代码的方式意味着第二种情况:行尾:
$ echo "19984 " | sed 's/19984 $/98400 /'
98400
$ echo "19984 something" | sed 's/19984 $/98400 /'
19984 something
so sed will match just the cases in which the line ends with 19984
. 所以sed将只匹配行以
19984
结尾的情况。 Otherwise it won't match. 否则,它将不匹配。
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