awk增加或更改文件中列的值

Question

I have a bash script that runs a backup job and produce a csv file.

90927597|1356976813998|90927598

How can I increment / change the value of the 3rd column of my CSV file? ( I actually just want to make it uniq using a random value).

How can I get that done?

Thank you

Answer 1

Given the file a , sed 's/hello/bye/ga' replaces all ocurrencies of hello with bye in the file a`.

$ cat a
90927597|1356976813998|90927598
$ sed 's/90927598/hello/g' a
90927597|1356976813998|hello
$ 
$ sed -i 's/90927598/hello/g' a
$ cat a
90927597|1356976813998|hello

that is, sed -i replaces the file. Without -i it shows the replacement on stdout.

---

each value in the third column with different value for each row, do you think its possible? just random, or use the same value + random value, the idea just to make it uniq

$ awk -v v=YOUR_SEED 'BEGIN {FS = "|"; OFS="|" } $3=++v' a > output_file

(idea got from jthill comment )