[英]java enum and postgresql enum
CREATE TABLE customers
(
first_name character varying(15),
second_name character varying(20),
login character varying(15) NOT NULL,
password character varying(15),
email character varying(40),
gender gender,
register_date date,
date_of_birth date,
address character varying(40),
address_number integer,
town character varying(20),
CONSTRAINT login PRIMARY KEY (login)
)
I have this table and I created an enum of gender such as:我有这张表,我创建了一个性别枚举,例如:
CREATE TYPE gender AS ENUM ( 'F', 'M',);
I am trying to insert into customers data from eclipse java with PreparedStatement but there is an error such as ERROR: column "gender" is of type gender but expression is of type character varying Hint: You will need to rewrite or cast the expression.我正在尝试使用 PreparedStatement 将来自 eclipse java 的客户数据插入到客户数据中,但出现错误,例如 ERROR: column "gender" is of type gender but expression is of type character varying 提示:您将需要重写或转换表达式。
My Java code looks like:我的 Java 代码如下所示:
PreparedStatement pre_state;
public enum gendertype {
F,
M;
}
pre_state = conn.prepareStatement("INSERT INTO"
+ " customers VALUES(?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)");
pre_state.set(6, gendertype.F.toString());
I can take no credit for this answer as you have already solved it, but I will explain why it works.我不能相信这个答案,因为你已经解决了它,但我会解释它为什么有效。
PostgreSQL provides the answer when it says PostgreSQL 在它说的时候提供了答案
Hint: You will need to rewrite or cast the expression
提示:您需要重写或强制转换表达式
The Java code is creating a string literal value that represents the Java enum gendertype type. Java 代码正在创建一个字符串文字值,该值表示 Java 枚举性别类型类型。
Casting a literal to a PostgreSQL gender type is done by adding a casting suffix to the value ::gender
.将文字转换为 PostgreSQL 性别类型是通过向值
::gender
添加转换后缀来完成的。
So valid input would be所以有效的输入将是
'F'::gender
or要么
'M'::gender
This works because all PostgreSQL types have a input method that takes a text representation and converts that to the internal form.这是有效的,因为所有 PostgreSQL 类型都有一个输入方法,它采用文本表示并将其转换为内部形式。
你的解决方案本来是
pre_state.setObject(6, gendertype.F.toString(), Types.OTHER);
In addition to other answers if you use for example createNativeQuery()
you should cast value to your enum
like cast(? as gender)
, something like that:除了其他答案,如果您使用例如
createNativeQuery()
,您应该将值转换为您的enum
,如cast(? as gender)
,类似这样:
Person person = new Person("Gurbanguly", "Berdymukhamedov", Gender.Male)
Session session = HibernateUtil.getSessionFactory().openSession();
Transaction transaction = session.beginTransaction();
session.createNativeQuery("INSERT INTO Person (firstname, lastname, gender) VALUES (?,?,cast(? as gender))")
.setParameter(1, person.getFirstName())
.setParameter(2, person.getLastName())
.setParameter(3, person.getGender().toString())
.executeUpdate();
transaction.commit();
session.close(); // this statement is needed not to produce many sessions
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