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JavaScript执行PHP代码

[英]javascript executing php code

i have a php web application project ... and i want to implement a javascript onclick code .. for example : when user clicks follow this post ... the MySQL query inserts into database that the user followed this ... so the page is refreshed and after that it will appear as FOLLOWED .. what's the javascript code needed to do this ... or is there any example may fit ?? 我有一个php Web应用程序项目...,我想实现一个javascript onclick代码..例如:当用户单击时,请遵循此信息... MySQL查询将插入到用户遵循此信息的数据库中。因此,该页面刷新后,它将显示为FOLLOWED ..进行此操作所需的javascript代码是什么?或者有没有合适的示例?

here's a sample code 这是示例代码

     <div id="main_content">


        <?php

        if(isset($_GET['et']))
        {
        $et = $_GET['et'];
        }
        $result = mysql_query("select * from events where event_type =$et") ;

        require_once('queries/category_extract.php') ;

        ?>

        <div id="body_content">
    <div id="event_tag">
        <a><?php echo $cattitle["categ_title"]?>s</a>
    </div>

    <?php
    while($row=mysql_fetch_array($result) )
    {

        require('queries/followers_extract.php') 
        ?>



        <div id="postpreview">
        <div id="postpreview_up">
            <div id="postpreview_up_left">
                    <div id="postpreview_up_left_left">
                        <a>Event Title :</a>
                    </div>

                    <div id="postpreview_up_left_right">
                    <a><?php echo $row["event_title"] ?></a> 
                    </div>
            </div>

              <div id="postpreview_up_right">
                <img src="images/read_more.gif" />
              </div>
        </div>

        <div id="postpreview_bottom">
            <div id="postpreview_bottom_left">
                <div id="postpreview_bottom_left_left">
                <a>Date :</a>
                </div>

                <div id="postpreview_bottom_left_right">
                <a><?php echo $row["event_date"] ?></a>
                </div>
            </div>
        <div id="postpreview_bottom_right">

                <div id="postpreview_bottom_right_left">
                <?php

                if($follower['follower_id'] ==NULL){echo " <img src='images/follow_button.jpg' /> " ; } 
                    else { echo " <img src='images/follow_closed.jpg' /> " ;}
                ?>
                </div>

                <div id="postpreview_bottom_right_right">
                <?php
                if($follower['follower_id'] !=NULL){ echo " <img src='images/following_button.jpg' /> " ; } 
                else { echo " <img src='images/following_Closed.jpg' /> " ;}

                ?>
                </div>
                <div id="postpreview_bottom_right_right">
                <?php
                if($follower['follower_id'] !=NULL){ echo " <img src='images/unfollow_button.jpg' /> " ; } 
                else { echo " <img src='images/unfollow_closed.jpg' />  " ;}

                ?>

                </div>

        </div>

        </div>

        </div>

        <div id="splitter"></div>
        <?php
    }
    ?>
   <!--End Of Post Preview-->

     <!--End Of Post Preview-->

ok go for this: http://www.9lessons.info/2009/04/exactly-twitter-like-follow-and-remove.html 好的,可以这样做: http : //www.9lessons.info/2009/04/exactly-twitter-like-follow-and-remove.html

you have to learn the basics as i read. 您必须阅读我所读的基础知识。

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